如何查看六个月前的活跃ID

Question

如何用一条语句将 ctc 求和到一行中，即 2023 年 1 月 1 日的 ID 在 2023 年 6 月 1 日仍然存在？所以我尝试了下面的语句但返回0！

SUM( CASE WHEN ID = LAG(ID) OVER (PARTITION BY GP ORDER BY Date- 5 MONTH) 
THEN SUM(FLOAT(value)) ELSE 0 END) AS count

我也尝试过这个：

case when date = Date- 5 MONTH then 
        coalesce(
            lag(value) over(
                partition by id, case when date = eDate- 5 MONTH then 1 else 0 end
                order by date
            ),
            0
        )
    end  AS PrevValue

dbfiddle 链接到示例数据！

Answer 1

使用相关子查询，如下所示：

WITH CUSTOMERS AS 
(
SELECT GP, ID, DATE(TO_DATE(DATE, 'MM/DD/YYYY')) AS DATE, CTC
FROM
(
VALUES
  ('AAAA', '001', '1/1/2023', 1)
, ('AAAA', '002', '1/1/2023', 1)
, ('AAAA', '003', '1/1/2023', 1)
, ('AAAA', '004', '1/1/2023', 0)
, ('AAAA', '001', '6/1/2023', 1)
, ('AAAA', '002', '6/1/2023', 1)
, ('AAAA', '005', '6/1/2023', 1)
, ('AAAA', '006', '6/1/2023', 1)
) CUSTOMERS (GP, ID, DATE, CTC)
)
SELECT 
  A.*
, A.CTC +
  COALESCE 
  (
    (
      SELECT SUM(B.CTC) 
      FROM CUSTOMERS B 
      WHERE B.ID = A.ID AND B.DATE = A.DATE - 5 MONTH
     )
   , 0
  ) AS CTC_SUM
FROM CUSTOMERS A

全科医生	身份证	日期	CTC	CTC_SUM
AAAA	001	2023-01-01	1	1
AAAA	002	2023-01-01	1	1
AAAA	003	2023-01-01	1	1
AAAA	004	2023-01-01	0	0
AAAA	001	2023-06-01	1	2
AAAA	002	2023-06-01	1	2
AAAA	005	2023-06-01	1	1
AAAA	006	2023-06-01	1	1

小提琴