SQL查询以查找平均点

Question

我有一个数据库，其中包含有关游戏的信息，其列如下：game

我正在尝试创建一个查询，以返回具有以下条件的2列team和average_score：1. avg_score是球队在“客场”比赛中的平均得分数（球队名称出现在away_team列中）2.仅包括至少参加过30场比赛的球队。3.仅按平均进球数降序返回前10名球队。

我已经尝试过以下查询：

    SELECT away_team AS team, round(avg(away_score),3) AS ave_goals 
    FROM results
    WHERE date >= 2000-01-01 AND neutral = 'FALSE'
    group by away_team HAVING COUNT(away_team) >=30
    ORDER BY ave_goals DESC
    LIMIT 10 

此查询未提供期望的结果。我究竟做错了什么？感谢您的帮助。

Answer 1

也许在可行的日期附近加上引号：

SELECT away_team AS team, round(avg(away_score),3) AS ave_goals 
FROM results
WHERE date >= '2000-01-01' AND neutral = 'FALSE'
GROUP BY away_team
HAVING COUNT(away_team) >=30
ORDER BY ave_goals DESC
LIMIT 10 

Answer 2

您的查询似乎正确，但似乎date条件不正确，我认为我们需要在您的中性列上添加upper()函数。

select * from 
    (select away_team as team
        , round(avg(away_score),3) as ave_goals
    from results
    where cast(date as date) >= '2000-01-01' and upper(neutral)='FALSE'
    group by away_team
    having count(away_team) >= 30) t1
order by t1.ave_goals desc
limit 10