我希望从给定的游戏列表中生成可能的总数，例如['France - Germany'。这样的总结果将是这种情况的3种可能的结果{主队胜利，他们并列，或客队胜利}。
1 FRANCE - GERMANY 1 2 FRANCE - GERMANY x 3 FRANCE - GERMANY 2
对于另一个案例，列表是['法国 - 德国'，'西班牙 - 意大利']
1 FRANCE - GERMANY 1 SPAIN - ITALIA 1 2 FRANCE - GERMANY 1 SPAIN - ITALIA x 3 FRANCE - GERMANY 1 SPAIN - ITALIA 2 4 FRANCE - GERMANY x SPAIN - ITALIA 1 5 FRANCE - GERMANY x SPAIN - ITALIA x 6 FRANCE - GERMANY x SPAIN - ITALIA 2 7 FRANCE - GERMANY 2 SPAIN - ITALIA 1 8 FRANCE - GERMANY 2 SPAIN - ITALIA x 9 FRANCE - GERMANY 2 SPAIN - ITALIA 2
以下是我的代码
import itertools
games = ['France - Germany']
case = ["1","X","2"]
results = []
for eachcase in case:
for game in games:
results.append("%s %s" % (game, eachcase))
print("\n".join(results)+ "\n %s" %len(results))
并且列表中项目的输出是
France - Germany 1
France - Germany X
France - Germany 2
这很好，但随着列表项目数量的增加，它不起作用。任何帮助解决这个问题将不胜感激提前:)
对于给定的游戏列表，我们可以使用itertools.product：
from itertools import product
def game_product(games):
for i, res in enumerate(product('1x2', repeat=len(games)), 1):
print(i)
for gr in zip(games, res):
print('{} {}'.format(*gr))
例如：
>>> game_product(['France - Germany', 'Spain - Italia', 'Brazil - Spain'])
1
France - Germany 1
Spain - Italia 1
Brazil - Spain 1
2
France - Germany 1
Spain - Italia 1
Brazil - Spain x
3
France - Germany 1
Spain - Italia 1
Brazil - Spain 2
4
France - Germany 1
Spain - Italia x
Brazil - Spain 1
5
France - Germany 1
Spain - Italia x
Brazil - Spain x
6
France - Germany 1
Spain - Italia x
Brazil - Spain 2
7
France - Germany 1
Spain - Italia 2
Brazil - Spain 1
8
France - Germany 1
Spain - Italia 2
Brazil - Spain x
9
France - Germany 1
Spain - Italia 2
Brazil - Spain 2
10
France - Germany x
Spain - Italia 1
Brazil - Spain 1
11
France - Germany x
Spain - Italia 1
Brazil - Spain x
12
France - Germany x
Spain - Italia 1
Brazil - Spain 2
13
France - Germany x
Spain - Italia x
Brazil - Spain 1
14
France - Germany x
Spain - Italia x
Brazil - Spain x
15
France - Germany x
Spain - Italia x
Brazil - Spain 2
16
France - Germany x
Spain - Italia 2
Brazil - Spain 1
17
France - Germany x
Spain - Italia 2
Brazil - Spain x
18
France - Germany x
Spain - Italia 2
Brazil - Spain 2
19
France - Germany 2
Spain - Italia 1
Brazil - Spain 1
20
France - Germany 2
Spain - Italia 1
Brazil - Spain x
21
France - Germany 2
Spain - Italia 1
Brazil - Spain 2
22
France - Germany 2
Spain - Italia x
Brazil - Spain 1
23
France - Germany 2
Spain - Italia x
Brazil - Spain x
24
France - Germany 2
Spain - Italia x
Brazil - Spain 2
25
France - Germany 2
Spain - Italia 2
Brazil - Spain 1
26
France - Germany 2
Spain - Italia 2
Brazil - Spain x
27
France - Germany 2
Spain - Italia 2
Brazil - Spain 2
您可以使用列表推导轻松完成此操作：
fg = [ ("FRANCE-GERMANY",outcome) for outcome in (1,"x",2) ]
for g1 in fg: print(g1)
print("")
si = [ ("SPAIN-ITALY",outcome) for outcome in (1,"x",2) ]
final = [ (g1,g2) for g1 in fg for g2 in si ]
for g1,g2 in final:
print(g1)
print(g2)
print("")
如果您想要更通用的方法，itertools模块中的产品功能也可以帮助：
from itertools import product
fg = list(product(["FRANCE-GERMANY"],(1,"x",2)))
si = list(product(["SPAIN-ITALY"],(1,"x",2)))
final = list(product(fg,si))
您可以将itertools.product与repeat参数一起使用，以创建与游戏总数一样多的游戏结果产品。
from itertools import product
games = ['France - Germany', 'Spain - Italia']
case = ["1","X","2"]
results = []
for i in product(case, repeat = len(games)):
results.append({k:v for k, v in zip(games, i)})
#if you prefer list of tuples instead, alternatively,
#results.append([(k, v) for k, v in zip(games, i)])
print(results)
输出：
[{'France - Germany': '1', 'Spain - Italia': '1'},
{'France - Germany': '1', 'Spain - Italia': 'X'},
{'France - Germany': '1', 'Spain - Italia': '2'},
{'France - Germany': 'X', 'Spain - Italia': '1'},
{'France - Germany': 'X', 'Spain - Italia': 'X'},
{'France - Germany': 'X', 'Spain - Italia': '2'},
{'France - Germany': '2', 'Spain - Italia': '1'},
{'France - Germany': '2', 'Spain - Italia': 'X'},
{'France - Germany': '2', 'Spain - Italia': '2'}]