应用程序崩溃:异常-无法识别的选择器发送到实例

问题描述 投票:0回答:3

我有一个UITableviewController,它具有以下逻辑,一旦键盘像这样切换,就可以上下滑动整个视图:

class ChatDetailViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {
 // variables...

 override func viewDidLoad() {
        super.viewDidLoad()
        // do stuff...
        NotificationCenter.default.addObserver(self, selector: Selector(("keyboardWillShow:")), name: UIResponder.keyboardWillShowNotification, object: nil)
        NotificationCenter.default.addObserver(self, selector: Selector(("keyboardWillHide:")), name: UIResponder.keyboardWillHideNotification, object: nil)
       // do other stuff...
}
...
func keyboardWillShow(notification: NSNotification) {
        if let keyboardSize = (notification.userInfo?[UIResponder.keyboardFrameBeginUserInfoKey] as? NSValue)?.cgRectValue {
            self.view.frame.origin.y -= keyboardSize.height
        }
    }

    func keyboardWillHide(notification: NSNotification) {
        self.view.frame.origin.y = 0
    }
...
}

切换键盘,然后使应用程序崩溃,但以下异常:ChatDetailViewController keyboardWillShow:]:无法识别的选择器已发送到实例0x7f82fc41fdf0

乍看起来,错误消息似乎很清楚,但是我仍然无法弄清楚选择器出了什么问题。没有代码警告,没有错别字,...

我在这里做错什么了?

swift nsnotificationcenter
3个回答
1
投票
override func viewDidLoad() { super.viewDidLoad() NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillShow), name: UIResponder.keyboardWillShowNotification, object: nil) NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillHide), name: UIResponder.keyboardWillHideNotification, object: nil) }

u忘记添加@objc部分


0
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三个问题:


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