FCGX_Accept_r 失败，返回代码为 -88

Question

我正在用 C++ 编写一个 fastcgi 应用程序，并且正在努力解决 FCGX_Accept_r() 退出而不阻塞且返回值为“-88”的问题。经过大量谷歌搜索后，我发现您必须正确初始化 FCGX 结构，更正 uds 套接字上的 umask，不要忘记 FCGX_Init() 并检查 FCGX_Init() 和 FCGX_InitRequest() 的返回代码。

我已经为我的程序完成了上述所有操作，但结果仍然相同。

所以我尝试从 fcgi 站点构建示例 C 应用程序：http://www.fastcgi.com/devkit/examples/threaded.c 然后它立即退出。

奇怪的是，他们那里没有任何打开的套接字。所以我添加了几行 - 打印出 FCGX_Accept_() 返回值并打开 uds 套接字。

这是生成的代码：

/*
 * threaded.c -- A simple multi-threaded FastCGI application.
 */

#ifndef lint
static const char rcsid[] = "$Id: threaded.c,v 1.9 2001/11/20 03:23:21 robs Exp $";
#endif /* not lint */

#include "fcgi_config.h"

#include <pthread.h>
#include <sys/types.h>
#include <sys/stat.h>

#ifdef HAVE_UNISTD_H
#include <unistd.h>
#endif

#include <stdio.h>
#include "fcgiapp.h"


#define THREAD_COUNT 20

static int counts[THREAD_COUNT];

static void *doit(void *a)
{
    int rc, i, thread_id = (int)a;
    pid_t pid = getpid();
    FCGX_Request request;
    char *server_name;

    FCGX_InitRequest(&request, 0, 0);

    for (;;)
    {
        static pthread_mutex_t accept_mutex = PTHREAD_MUTEX_INITIALIZER;
        static pthread_mutex_t counts_mutex = PTHREAD_MUTEX_INITIALIZER;

        /* Some platforms require accept() serialization, some don't.. */
        pthread_mutex_lock(&accept_mutex);
        rc = FCGX_Accept_r(&request);
        pthread_mutex_unlock(&accept_mutex);

        if (rc < 0) {
        printf("failed accept: %d\n", rc);
            break;
    }

        server_name = FCGX_GetParam("SERVER_NAME", request.envp);

        FCGX_FPrintF(request.out,
            "Content-type: text/html\r\n"
            "\r\n"
            "<title>FastCGI Hello! (multi-threaded C, fcgiapp library)</title>"
            "<h1>FastCGI Hello! (multi-threaded C, fcgiapp library)</h1>"
            "Thread %d, Process %ld<p>"
            "Request counts for %d threads running on host <i>%s</i><p><code>",
            thread_id, pid, THREAD_COUNT, server_name ? server_name : "?");

        sleep(2);

        pthread_mutex_lock(&counts_mutex);
        ++counts[thread_id];
        for (i = 0; i < THREAD_COUNT; i++)
            FCGX_FPrintF(request.out, "%5d " , counts[i]);
        pthread_mutex_unlock(&counts_mutex);

        FCGX_Finish_r(&request);
    }

    return NULL;
}

int main(void)
{
    int i;
    pthread_t id[THREAD_COUNT];

    FCGX_Init();

    umask(0);
    FCGX_OpenSocket("/tmp/fcgi.sock", 10);

    for (i = 1; i < THREAD_COUNT; i++)
        pthread_create(&id[i], NULL, doit, (void*)i);

    doit(0);

    return 0;
}

你猜怎么着：

# gcc fcgi.c -lpthread -lfcgi         
# ./a.out
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -88
failed accept: -failed accept: -88

有人可以指出我做错了什么吗？ 谢谢！

更新：

有趣的是这里的例子https://habrahabr.ru/post/154187/有效。而且我看不出有多大区别。

Answer 1

问题是在他们使用的示例中

FCGX_InitRequest(&request, 0, 0);

而第二个参数必须是套接字 ID。伙计们，很好的例子。

Answer 2

您必须使用 unix 套接字处理 fastCGI 调用，如下所示：

    int socketId = FCGX_OpenSocket("/tmp/fcgi.sock", SOMAXCONN);
    if (socketId < 0) {
            std::cerr << "Error opening socket" << std::endl;
            return 1;
    }

    FCGX_Init();
    FCGX_Request request;

    FCGX_InitRequest(&request, socketId, 0);
    while (FCGX_Accept_r(&request) == 0) {
    // Handle request
    }