我正在使用play 2.8.x framework
,并且具有以下控制器:
public class HomeController extends Controller {
public Result show(Http.Request request) throws MyException {
...
return ok("some_data");
}
}
而且我想在Spring framework
中做类似的事情来处理异常:
// It is from the Spring web framework
@ExceptionHandler(MyException.class)
@ResponseStatus(HttpStatus.BAD_REQUEST)
public ExplainExceptionDTO handleMyException() {
...
return explain;
}
我可以在play 2.8.x framework
中做类似的事情吗?
这很好解释:https://www.playframework.com/documentation/2.8.x/JavaErrorHandling
@Singleton
public class ErrorHandler implements HttpErrorHandler {
public CompletionStage<Result> onClientError(
RequestHeader request, int statusCode, String message) {
return CompletableFuture.completedFuture(
Results.status(statusCode, "A client error occurred: " + message));
}
public CompletionStage<Result> onServerError(RequestHeader request, Throwable exception) {
return CompletableFuture.completedFuture(
Results.internalServerError("A server error occurred: " + exception.getMessage()));
}
}
您感兴趣的方法是onServerError
。因此,如果不是您的异常返回badRequest()
,则无需返回默认的internalServerError检查Throwable类型,甚至可以根据需要提供模板。