我知道关于将awk输出保存到堆栈溢出时可用的变量有太多问题,但是我已经尝试了所有可能的答案,但似乎没有用。请使用以下代码帮助我。
我已经尝试了以下类型的解决方案,但是在回显时,它们全都给了我空白的输出。
案例1:
sshpass -p$password ssh -T -o StrictHostKeyChecking=no $hostname <<EOF
tomcat=`ps -ef | grep -i tomcat | grep -i bootstrap | awk '{print \$2}' `
httpd=`systemctl status httpd | awk 'NR==3 {print \$2}'`
echo $tomcat
echo $httpd
EOF
案例2:
sshpass -p$password ssh -T -o StrictHostKeyChecking=no $hostname <<EOF
tomcat=$(ps -ef | grep -i tomcat | grep -i bootstrap | awk '{print \$2}')
httpd=$(systemctl status httpd | awk 'NR==3 {print \$2}')
echo $tomcat
echo $httpd
EOF
案例3:
sshpass -p$password ssh -T -o StrictHostKeyChecking=no $hostname <<EOF
tomcat=`ps -ef | grep -i tomcat | grep -i bootstrap | awk '{print $2}' `
httpd=`systemctl status httpd | awk 'NR==3 {print $2}'`
echo $tomcat
echo $httpd
EOF
案例4:
sshpass -p$password ssh -T -o StrictHostKeyChecking=no $hostname <<EOF
tomcat=$(ps -ef | grep -i tomcat | grep -i bootstrap | awk '{print $2}')
httpd=$(systemctl status httpd | awk 'NR==3 {print $2}')
echo $tomcat
echo $httpd
EOF
请帮帮我。
谢谢,
Sid
您尝试过这种方式吗?
tomcat=$(sshpass -p$password ssh -T -o StrictHostKeyChecking=no $hostname "ps -ef | grep -i tomcat | grep -i bootstrap | awk '{print $2}'")
httpd=$(sshpass -p$password ssh -T -o StrictHostKeyChecking=no $hostname "systemctl status httpd | awk 'NR==3 {print $2}'")
echo $tomcat
echo $httpd