我需要编写一个带有“获取航班信息”按钮的网页。当用户单击此按钮时,编写一个AJAX调用以获取您在问题1中编写的XML文件,将XML解析为Javascript对象,然后将Javascript对象完全显示在网页上如下:
到目前为止是我的代码。我对此非常陌生,所以请放轻松吧! :
XML:
<?xml version="1.0" encoding="UTF-8"?>
<flightInfo>
<Date>02OCT19</Date>
<Flight> VA 1429 </Flight>
<Depart>Sydney</Depart>
<Arrive>Cairns</Arrive>
<Boarding>Gate 35 At 1855</Boarding>
<Carrier>Virgin Australia</Carrier>
</flightInfo>
<?xml version="1.0" encoding="UTF-8"?>
HTML:
<html>
<style>
table,th,td {
border : 1px solid black;
border-collapse: collapse;
}
th,td {
padding: 5px;
}
</style>
<body>
<button type="button" onclick="loadDoc()">Get flight
information</button>
<br><br>
<table id="demo"></table>
<script>
function loadDoc() {
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
myFunction(this);
}
};
xhttp.open("GET", "Question1.xml", true);
xhttp.send();
}
function myFunction(xml) {
var i;
var xmlDoc = xml.responseXML;
var table="<tr><th>Depart</th><th>Arrive</th></tr>";
var x = xmlDoc.getElementsByTagName("CD");
for (i = 0; i <x.length; i++) {
table += "<tr><td>" +
x[i].getElementsByTagName("Depart")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("Arrive")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("Date")[0].childNodes[0].nodeValue +
"</td></tr>";
}
document.getElementById("demo").innerHTML = table;
}
</script>
</body>
</html>
$(function(){
var data = '<?xml version="1.0" encoding="UTF-8"?><flightInfo><Date>02OCT19</Date><Flight> VA 1429 </Flight><Depart>Sydney</Depart><Arrive>Cairns</Arrive><Boarding>Gate 35 At 1855</Boarding><Carrier>Virgin Australia</Carrier></flightInfo>'
//Parse the givn XML
var xmlDoc1 = $.parseXML( data );
var $xml1 = $(xmlDoc1);
// Find Person Tag
var $flightInfo = $xml1.find("flightInfo");
$flightInfo.each(function(){
var Date = $(this).find('Date').text(),
Depart = $(this).find('Depart').text(),
Arrive = $(this).find('Arrive').text() ;
$("#data" ).append('<li>' + Date + ' - ' + Depart+ ' - ' + Arrive + '</li>');
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul id="data"></ul>
首先,您需要按如下所示解析xml对象中的数据,然后才能读取它。请尝试以下解决方案。<ul id="data"></ul> <script> $(function(){ var data = '<?xml version="1.0" encoding="UTF-8"?><flightInfo><Date>02OCT19</Date><Flight> VA 1429 </Flight><Depart>Sydney</Depart><Arrive>Cairns</Arrive><Boarding>Gate 35 At 1855</Boarding><Carrier>Virgin Australia</Carrier></flightInfo>' //Parse the givn XML var xmlDoc1 = $.parseXML( data ); var $xml1 = $(xmlDoc1); // Find Person Tag var $flightInfo = $xml1.find("flightInfo"); $flightInfo.each(function(){ var Date = $(this).find('Date').text(), Depart = $(this).find('Depart').text(), Arrive = $(this).find('Arrive').text() ; $("#data" ).append('<li>' + Date + ' - ' + Depart+ ' - ' + Arrive + '</li>'); }); }); </script>
查看实时演示:
http://jsfiddle.net/ru92p4en/