我需要创建一个按钮来在Java fx中打开一个窗口。不摇摆。没有fxml。
A。你可以有多个舞台吗?我认为不是,但是我看到一个网站在说其他话。
B。我是否必须使按钮创建一个扩展应用程序的类,覆盖start()...
我看了以下都无济于事。我看了很多东西,我只是不明白那里有什么或如何实现它。如何修改我的代码以使其正常工作?
https://o7planning.org/en/11533/opening-a-new-window-in-javafx
https://coderanch.com/t/663804/java/call-window-click-button-current
https://o7planning.org/en/11533/opening-a-new-window-in-javafx
Button to push new customers onto queue. Opens a new popu window (stage) to enter customer information.
btSave.setText("Add");
btSave.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
//SCENE 3 OF 3: ADD SCENE, Pane & Nodes
GridPane addPane = new GridPane();
//add nodes
addPane.add(new Label("Customer Name"), 1,1);
addPane.add(tfName, 1,2);
addPane.add(new Label("Size of Party"), 1,3);
addPane.add(tfParty, 1,4);
addPane.add(new Label("Customer Phone Number"), 1,5);
addPane.add(tfPhone, 1,6);
addPane.add(btSave, 1, 7);
Scene addScene = new Scene(addPane, 300, 250);
primaryStage.setTitle("Add Customer to Queue");
primaryStage.setScene(addScene);
primaryStage.show();
// Customer cust = new Customer();
// cust.name = tfName.getText();
// cust.party = Integer.parseInt(tfParty.getText());
// cust.phone = Integer.parseInt(tfPhone.getText());
// qLine.offer(cust);
}
});
I would like the button to show "Add" and would like it to open a new window when clicked.
如果您询问打开一个新舞台,以下代码可能会为您提供帮助。
Button btSave = new Button();
btSave.setText("Add");
btSave.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
//SCENE 3 OF 3: ADD SCENE, Pane & Nodes
GridPane addPane = new GridPane();
//add nodes
addPane.add(new Label("Customer Name"), 1,1);
addPane.add(tfName, 1,2);
addPane.add(new Label("Size of Party"), 1,3);
addPane.add(tfParty, 1,4);
addPane.add(new Label("Customer Phone Number"), 1,5);
addPane.add(tfPhone, 1,6);
addPane.add(btSave, 1, 7);
Stage addStage = new Stage();
Scene addScene = new Scene(addPane, 300, 250);
addStage.setTitle("Add Customer to Queue");
addStage.setScene(addScene);
addStage.show();
}
});