Flutter应用中如何向用户请求用户允许拨打iOS电话？

Question

我的应用程序具有拨打电话的代码，但首先请求用户许可。如果可能的话，我需要在通话期间直接获得许可。

Future<void> _makePhoneCall() async {
    if (Platform.isAndroid) {
      final callPermissionStatus = await Permission.phone.request();
      if (callPermissionStatus.isGranted) {
        final String userPhone = contactPhone;
        try {
          const MethodChannel('caller').invokeMethod('makeCall', userPhone);
        } on PlatformException catch (e) {
          Fluttertoast.showToast(
            msg: AppLocalizations.instance.translate("failedToCallTheNumber") +
                ("$contactPhone, ${e.message}"),
          );
        }
      } else {
        Fluttertoast.showToast(
          msg: AppLocalizations.instance.translate("failedToCallTheNumber") +
              ("$contactPhone"),
        );
      }
    } else if (Platform.isIOS) {
      final callPermissionStatus = await Permission.phone.request();
      if (callPermissionStatus.isGranted) {
        final String userPhone = contactPhone;
        try {
          const MethodChannel('caller')
              .invokeMethod('makeCall', userPhone);
        } on PlatformException catch (e) {
          Fluttertoast.showToast(
            msg: AppLocalizations.instance.translate("failedToCallTheNumber") +
                (" $contactPhone, ${e.message}"),
          );
        }
      } else {
        final String userPhone = contactPhone;
        Fluttertoast.showToast(
          msg: AppLocalizations.instance.translate("failedToCallTheNumber") +
              (" $userPhone"),
        );
      }
    }
  }

此代码在 Android 上运行良好，但在 iOS 上没有对话框询问用户权限。我正在使用permission_handler：^11.3.1

但是在permission_handler的文档中：^11.3.1我找到了“电话”的描述 -

/// Permission for accessing the device's phone state (Android only). static const phone = PermissionWithService._(8); 

除了“电话”之外，我应该使用什么来打开 iOS 的电话通话权限对话框？ 或者我应该使用另一个库而不是permission_handler？

我的扑医生-

Doctor summary (to see all details, run flutter doctor -v):
[✓] Flutter (Channel stable, 3.19.5, on macOS 14.4.1 23E224 darwin-arm64, locale ru-UA)
[✓] Android toolchain - develop for Android devices (Android SDK version 34.0.0)
[✓] Xcode - develop for iOS and macOS (Xcode 15.3)
[✓] Chrome - develop for the web
[✓] Android Studio (version 2023.2)
[✓] VS Code (version 1.87.2)
[✓] VS Code (version 1.87.2)
[✓] Connected device (3 available)
[✓] Network resources

• No issues found!

如果您在线更换 -

final callPermissionStatus = await Permission.phone.request();

• “电话”与“联系人” - 然后出现一个对话框，请求访问联系人的权限。

我还将这些行添加到 info.plist

<key>LSApplicationQueriesSchemes</key>
    <array>
    <string>needed to make phone calls</string>
    </array>
    <key>NSCallKitUsageDescription</key>
    <string>Call access permission is required to make calls.</string>
    <key>NSContactsUsageDescription</key>
    <string>Permission to access contacts is required to make calls.</string>
    <key>NSMicrophoneUsageDescription</key>
    <string>Permission to access the microphone is required to make calls.</string>

我不确定是否需要所有这些线路，我尝试添加所有内容以允许拨打电话。