SQL Server
我有一个带有2个时间戳的表,time_start和time_end。例如
ID time_start time_end
---- ------------------- -------------------
1 2019-01-01 08:30:00 2019-01-01 09:40:00
2 2019-01-01 09:10:24 2019-01-01 15:14:19
3 2019-01-01 09:21:15 2019-01-01 09:21:19
4 2019-01-01 10:39:45 2019-01-01 10:58:12
5 2019-01-01 11:39:45 2019-01-01 11:40:10
并且我想对它们进行分组,这样我可以将行数按可变的时间间隔分组。例如
time_interval row_count
------------------- ---------
2019-01-01 07:00:00 0
2019-01-01 08:00:00 1
2019-01-01 09:00:00 3
2019-01-01 10:00:00 2
2019-01-01 11:00:00 1
2019-01-01 12:00:00 0
我的时间间隔可能是1小时,1分钟,30分钟,1天等...
将其视为登录/注销的情况,我想看看在给定的分钟,小时,天等情况下用户如何登录?
嗨,这是我的解决方法。我用您的数据创建了一个表“ test”。
首先,我获得最小和最大间隔,然后,我使用CTE获得这些值之间的所有间隔。最后,有了这个CTE和一个在time_start和time_end之间间隔的左连接,我得到了答案。
此间隔为1小时
DECLARE @minDate AS DATETIME;
DECLARE @maxDate AS DATETIME;
SET @minDate = (select case
when (select min(time_start) from test) < (select min(time_end) from test)
then (select min(time_start) from test)
else (select min(time_end) from test) end )
SET @minDate = FORMAT(@minDate, 'dd-MM.yyyy HH:00:00')
SET @maxDate = (select case
when (select max(time_start) from test) > (select max(time_end) from test)
then (select max(time_start) from test)
else (select max(time_end) from test) end )
SET @maxDate = FORMAT(@maxDate, 'dd-MM.yyyy HH:00:00')
;WITH Dates_CTE
AS (SELECT @minDate AS Dates
UNION ALL
SELECT Dateadd(hh, 1, Dates)
FROM Dates_CTE
WHERE Dates < @maxDate)
SELECT d.Dates as time_interval, count(*) as row_count
FROM Dates_CTE d
LEFT JOIN test t on d.Dates
between (FORMAT(t.time_start, 'dd-MM.yyyy HH:00:00'))
and (FORMAT(t.time_end, 'dd-MM.yyyy HH:00:00'))
GROUP BY d.Dates
每隔10分钟,您需要进行一些更改。首先,我格式化日期以获取分钟数(dd-MM.yyyy HH:mm:00 instead of dd-MM.yyyy HH:00:00)
然后在左侧联接中,将time_start和time_end接近其10分钟的时间(9:30:00中的9:32:00)(dateadd(minute, 10 * (datediff(minute, 0, time_start) / 10), 0))
:
DECLARE @minDate AS DATETIME;
DECLARE @maxDate AS DATETIME;
SET @minDate = (select case
when (select min(time_start) from test) < (select min(time_end) from test)
then (select min(time_start) from test)
else (select min(time_end) from test) end )
SET @minDate = FORMAT(@minDate, 'dd-MM.yyyy HH:mm:00')
SET @maxDate = (select case
when (select max(time_start) from test) > (select max(time_end) from test)
then (select max(time_start) from test)
else (select max(time_end) from test) end )
SET @maxDate = FORMAT(@maxDate, 'dd-MM.yyyy HH:mm:00')
;WITH Dates_CTE
AS (SELECT @minDate AS Dates
UNION ALL
SELECT Dateadd(minute, 10, Dates)
FROM Dates_CTE
WHERE Dates < @maxDate)
SELECT d.Dates as time_interval, count(*) as row_count
FROM Dates_CTE d
LEFT JOIN test t on d.Dates
between dateadd(minute, 10 * (datediff(minute, 0, time_start) / 10), 0)
and dateadd(minute, 10 * (datediff(minute, 0, time_end) / 10), 0)
GROUP BY d.Dates
最后我以1小时的间隔得到了这个结果:
+---------------------+-----------+
| time_interval | row_count |
+---------------------+-----------+
| 01/01/2019 08:00:00 | 1 |
| 01/01/2019 09:00:00 | 3 |
| 01/01/2019 10:00:00 | 2 |
| 01/01/2019 11:00:00 | 2 |
| 01/01/2019 12:00:00 | 1 |
| 01/01/2019 13:00:00 | 1 |
| 01/01/2019 14:00:00 | 1 |
| 01/01/2019 15:00:00 | 1 |
+---------------------+-----------+
我希望它对您有用。
尝试一下,
DECLARE @start_date datetime='2019-01-01',
@end_date datetime='2019-01-02',
@i_minutes int=60
DECLARE @t TABLE
(
id int identity(1,1),time_start datetime,time_end datetime
)
INSERT INTO @t(time_start,time_end)VALUES
('2019-01-01 08:30:00','2019-01-01 09:40:00'),
('2019-01-01 09:10:24','2019-01-01 15:14:19'),
('2019-01-01 09:21:15','2019-01-01 09:21:19'),
('2019-01-01 10:39:45','2019-01-01 10:58:12'),
('2019-01-01 11:39:45','2019-01-01 11:40:10')
--SELECT @start_date=min(time_start),@end_date=max(time_end)
--FROM @t
;WITH CTE_time_Interval AS
(
SELECT @start_date AS time_int,@i_minutes AS i_minutes
UNION ALL
SELECT dateadd(minute,@i_minutes,time_int),i_minutes+ @i_minutes
FROM CTE_time_Interval
WHERE time_int<=@end_date
)
,CTE1 AS
(
SELECT ROW_NUMBER()OVER(ORDER BY time_int)AS r_no,time_int
FROM CTE_time_Interval
)
,CTE2 AS
(
SELECT a.time_int AS Int_start_time,b.time_int AS Int_end_time
FROM CTE1 a
INNER JOIN CTE1 b ON a.r_no+1=b.r_no
)
SELECT a.Int_start_time,a.Int_end_time,sum(iif(b.time_start is not null,1,0)) AS cnt
FROM CTE2 a
LEFT JOIN @t b ON
(
b.time_start BETWEEN a.Int_start_time AND a.Int_end_time
OR
b.time_end BETWEEN a.Int_start_time AND a.Int_end_time
OR
a.Int_start_time BETWEEN b.time_start AND b.time_end
OR
a.Int_end_time BETWEEN b.time_start AND b.time_end
)
GROUP BY a.Int_start_time,a.Int_end_time