彩票程序忽略功能

Question

我是要编写一个程序，该程序在另一个随机数之后列出，它确实会列出（同时发出哔声）。但是，它忽略了程序正常运行所需的基本功能。 ask（）函数执行其含义，它要求用户输入范围（1000-9999）之间的整数，然后将其与中奖号码（随机数）进行比较，以查看用户是否正确猜中了中奖号码。我只是最近才开始用Java编写程序，所以我不太确定自己是否犯了基本错误。任何帮助，将不胜感激！

package edu.pupr.pega4;
import java.awt.Toolkit;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Date;
import java.util.Scanner;
import javax.swing.JOptionPane;
import javax.swing.Timer;
public class Pega4Driver {
    public static void main(String[] args) {
        Pega4 test = new Pega4(2000, true);
        test.start();
        JOptionPane.showMessageDialog(null, "Quit program?");
        JOptionPane.showMessageDialog(null, "Perdiste!!!");
        System.exit(0);
    }
}

class Pega4 {
    private int interval; //Time interval for new number to appear
    private boolean beep; //BEEP
    private int number; //The input number
    private int tiradas = 1; //Counter
    private int winNum; //The winning number 
    //Constructor
    public Pega4(int interval, boolean beep) {
        this.interval = interval;
        this.beep = beep;
    }
    //Returns a random number within a specified range
    public double getRandomIntegerBetweenRange(double min, double max){
        double x = (int)(Math.random()*((max-min)+1))+min;
        return x;
    }
    public void start() {
        class Pega4Inner implements Asker, ActionListener {
            Scanner input = new Scanner(System.in);
            Date now = new Date();
            @Override
            public void ask() {
                System.out.println("Entrar numero deseado: ");
                number = input.nextInt();
                //Input Validation
                if (number < 1000 || number > 9999)
                {
                    System.out.println("Entrada invalida. Entrar numero deseado: ");
                    number = input.nextInt();
                }
                System.out.println(now);
            }
            @Override
            public void actionPerformed(ActionEvent e) {
                winNum = (int) getRandomIntegerBetweenRange(1000, 9999);
                System.out.println("Tirada #" + (tiradas++) + ": " + winNum);
                if (beep)
                    Toolkit.getDefaultToolkit().beep();
                if (winNum == number)
                {
                    JOptionPane.showMessageDialog(null, "Ganaste!!!");
                    System.exit(0);
                }
            }
        }
        ActionListener listener = new Pega4Inner();
        Timer timer = new Timer(interval, listener);
        timer.start();
    }
}

Pega4Inner类实现了我创建的名为Asker的接口。其代码如下：

package edu.pupr.pega4;

public interface Asker {
    void ask();
}

Answer 1

 public void actionPerformed(ActionEvent e) {
     ask();
     winNum = (int) getRandomIntegerBetweenRange(1000, 9999);
     ...