python tkinter界面如何创建新的显示txt文件

Question

我构建了一个代码，该代码需要python用户输入，并在按下应用程序时将其插入文本文件中，如下面的图片所示>>

并且当用户插入新文本时，文本文件将总是被更新，如何在旁边创建一个新按钮以向用户显示最新的文本文件

并希望防止输入相同的文本例如，如果文本文件中有一个（go），则程序不再输入（go）这是我的代码

root = Tk()

ivn = StringVar()
inputVarName = Entry(root, textvariable=str(ivn))
ivn.set(str("text1"))
inputVarName.grid(row=0, column=0)

ivn2 = StringVar()
inputVarName2 = Entry(root, textvariable=str(ivn2))
ivn2.set(str("text2"))
inputVarName2.grid(row=1, column=0)




def writetofile():
    content_list = [ivn.get(), ivn2.get()]

    print("\n".join(content_list))    
    with open("help.txt", "a") as f:
        for item in content_list:
            f.write("%s\n" % item)

applyButton = Button(root, text="Apply", command=writetofile)
applyButton.grid(row=2, column=1)



root.mainloop()

<<

我正在尝试相同的东西，但是输出一个

import tkinter.ttk as ttk
import tkMessageBox

root = Tk()
root.geometry("500x300")
root.title("The Gatway company")

ivn = StringVar()
inputVarName = Entry(root, textvariable=str(ivn))
ivn.set(str("text1"))
inputVarName.grid(row=0, column=0,columnspan=2)
def writetofile():
    content_list = [ivn.get()]
    if any(content_list):


        with open("help.txt", 'r+') as inFile:
            for item in content_list:
                if ("%s\n" % item).encode('UTF-8') in inFile:
                    tkMessageBox.showwarning("Warning", "'%s': Already exists!" % item)
                    return

        with open("help.txt", "a") as f:
            for item in content_list:
                f.write( ("%s\n" % item).encode('UTF-8'))

    ivn.set('')

def showfile():
    top = Toplevel()
    top.title("help.txt")
    textArea = Text(top)

    scrollbar = ttk.Scrollbar(top, command=textArea.yview)
    scrollbar.grid(row=0, column=1, sticky='nsew')

    textArea['yscrollcommand'] = scrollbar.set

    with open("help.txt", "r") as infile:
        textArea.insert(END, infile.read())

    textArea.grid(row=0, column=0)
    textArea.config(state=DISABLED)

applyButton = Button(root, text="Apply", command=writetofile)
applyButton.grid(row=2, column=0, sticky=W+E)
applyButton.config( height = 5, width = 10 )

showButton = Button(root, text="Show", command=showfile)
showButton.grid(row=2, column=1, sticky=W+E)
showButton.config( height = 5, width = 10 ) 



root.mainloop()

与您的代码相同，但是对于一个条目，我正在考虑以一种用户可以选择help.txt文件的方式（如文件请求者）的方式对其进行编辑。

为了防止用户插入相同的文本，只需清空两个条目，您可以在保存到文件之前检查条目是否不为空。
您可以使用顶级窗口显示文件内容。
检查以下示例：
from tkinter import Tk, Toplevel, Button, Entry, StringVar, Text, DISABLED, END, W, E 
import tkinter.ttk as ttk
import tkMessageBox

root = Tk()


ivn = StringVar()
inputVarName = Entry(root, textvariable=str(ivn))
ivn.set(str("text1"))
inputVarName.grid(row=0, column=0,columnspan=2)

ivn2 = StringVar()
inputVarName2 = Entry(root, textvariable=str(ivn2))
ivn2.set(str("text2"))
inputVarName2.grid(row=1, column=0,columnspan=2)


def writetofile():
    content_list = [ivn.get(), ivn2.get()]
    if any(content_list):
        print("\n".join(content_list))

        with open("help.txt", 'r+') as inFile:
            for item in content_list:
                if ("%s\n" % item).encode('UTF-8') in inFile:
                    tkMessageBox.showwarning("Warning", "'%s': Already exists!" % item)
                    return

        with open("help.txt", "a") as f:
            for item in content_list:
                f.write( ("%s\n" % item).encode('UTF-8'))

    ivn.set('')
    ivn2.set('')


def showfile():
    top = Toplevel()
    top.title("help.txt")
    textArea = Text(top)

    scrollbar = ttk.Scrollbar(top, command=textArea.yview)
    scrollbar.grid(row=0, column=1, sticky='nsew')

    textArea['yscrollcommand'] = scrollbar.set

    with open("help.txt", "r") as infile:
        textArea.insert(END, infile.read())

    textArea.grid(row=0, column=0)
    textArea.config(state=DISABLED)

applyButton = Button(root, text="Apply", command=writetofile)
applyButton.grid(row=2, column=0, sticky=W+E)

showButton = Button(root, text="Show", command=showfile)
showButton.grid(row=2, column=1, sticky=W+E)



root.mainloop()
编辑为在评论中回答@IbrahimOzaeri问题。您可以使用tkFileDialog.askopenfilename要求用户选择文件：
from Tkinter import Tk
import Tkinter, Tkconstants, tkFileDialog

root = Tk()
root.filename = tkFileDialog.askopenfilename(initialdir = "/",title = "Select file",filetypes = (("text files","*.txt"),("all files","*.*")))
print (root.filename)

Answer 1

Answer 2

您可以使用顶级窗口显示文件内容。