我想在 Flutter App 的 Listview 中显示我的 Json 数据

Question

我想在列表视图中显示我所有的 json 数据。但问题是，当我想在listview中获取idEmployee、officeID、avater和fullName时，就会显示错误。

类型“String”不是“int”类型的子类型。

当我想使用 FutureBuilder 仅显示 fullName 时，如果我在模型类中注释了所有没有 fullName 的变量，则效果很好。但是当我想添加没有 fullName 的任何其他数据时，它显示错误。

这是我想在listview中显示的json数据：

{
    "success": true,
    "data": {
        "count": 259,
        "data": [
            {
                "idEmployee": 3559,
                "avatar": "f8b8ad832a591db9c86a157a3739d98b.jpg",
                "fullName": "A X C",
                "officeID": "1003559",
                "email": "",
                "designation": "Account Manager",
                "department": "Accounts",
                "mobileNumber": "",
                "workStation": "Software Office",
                "businessUnit": "EMD"
            }
        ]
    },
    "id": 2899
}

这是我的模型类：

class ListAlbum {
  final int idEmployee;
  final String avatar;
  final String fullName;
  final int officeID;
  final String email;
  final String designation;
  final String department;
  final String mobileNumber;
  final String workStation;
  final String businessUnit;

  ListAlbum({
    required this.idEmployee,
    required this.avatar,
    required this.fullName,
    required this.officeID,
    required this.email,
    required this.designation,
    required this.department,
    required this.mobileNumber,
    required this.workStation,
    required this.businessUnit,
  });

  factory ListAlbum.fromJson(Map<String, dynamic> json) {
    return ListAlbum(
      idEmployee: json['idEmployee'],
      avatar: json['avatar'],
      fullName: json['fullName'],
      officeID: json['officeID'],
      email: json['email'],
      designation: json['designation'],
      department: json['department'],
      mobileNumber: json['mobileNumber'],
      workStation: json['workStation'],
      businessUnit: json['businessUnit'],
    );
  }
}

这是我的完整代码。

现在我想通过解决这些错误来在 Scaffold 中创建并添加带有数据的列表视图。我怎样才能创建这个列表视图？

class OrganizationList extends StatefulWidget {
  const OrganizationList({Key? key}) : super(key: key);

  @override
  _OrganizationListState createState() => _OrganizationListState();
}

class _OrganizationListState extends State<OrganizationList> {
  late Future<ListAlbum> futureAlbum;

  @override
  void initState() {
    super.initState();
    futureAlbum = listData();
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: Center(
        child: FutureBuilder<ListAlbum>(
          future: futureAlbum,
          builder: (context, snapshot) {
            if (snapshot.hasData) {
              print(snapshot.data);
              return Text(snapshot.data!.fullName);
              // return Text(snapshot.data!.officeID.toString());   // in this line error shows. type 'String' in not a subtype of type 'int'
            } else if (snapshot.hasError) {
              return Text('${snapshot.error}');
            }
            return const CircularProgressIndicator();
          },
        ),
      ),
    );
  }
}

Future<ListAlbum> listData() async {
  final token = 'eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJzdWIiOjI4OTksImlzcyI6Imh0dHBzOi8vcG9ydGFsLWFwaS5qb21ha2hhdGEuY29tL2FwaS9hdXRoL2xvZ2luIiwiaWF0IjoxNjI5NTI2OTc1LCJleHAiOjE2Mjk2MTMzNzUsIm5iZiI6MTYyOTUyNjk3NSwianRpIjoiRktiT295eEYwaEpDUXMxdiJ9.o4eM_C4hlluHe9Azk0MspPJtYZ7agdpFA6xwKiijLj8';
  String url =
      'https://portal-api.jomakhata.com/api/getOrganizationData?token=${token}';

  Dio dio = new Dio();
  dio.options.headers['Content-Type'] = 'application/json';
  final body = {'limit': 10, 'orderBy': 'idEmployee', 'orderType': 'DESC'};
  final response = await dio.post(url, data: body);

  if (response.statusCode == 200) {
    print(response.statusCode);
    print(response.data);
    var data = ListAlbum.fromJson(response.data["data"]["data"][0]);
    return data;
  } else {
    throw Exception('Failed!');
  }
}

Answer 1

根据您的json数据，您的

officeID

是一个字符串

"officeID": "1003559",

但是在

ListAlbum

中，属性被定义为整数

final int officeID;

将

final int officeID;

中的

ListAlbum

更改为

final String officeID;

并且不再需要

.toString()

。

根据OP请求进行编辑以获取更多帮助：

谢谢你。我明白了。我的问题是什么。这对我来说是一个愚蠢的错误。你能帮我在 Scaffold 中创建 listview 来显示这些数据吗？

Future<List<ListAlbum>> listData() async {
  final token = 'eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJzdWIiOjI4OTksImlzcyI6Imh0dHBzOi8vcG9ydGFsLWFwaS5qb21ha2hhdGEuY29tL2FwaS9hdXRoL2xvZ2luIiwiaWF0IjoxNjI5NTI2OTc1LCJleHAiOjE2Mjk2MTMzNzUsIm5iZiI6MTYyOTUyNjk3NSwianRpIjoiRktiT295eEYwaEpDUXMxdiJ9.o4eM_C4hlluHe9Azk0MspPJtYZ7agdpFA6xwKiijLj8';
  String url =
      'https://portal-api.jomakhata.com/api/getOrganizationData?token=${token}';

  Dio dio = new Dio();
  dio.options.headers['Content-Type'] = 'application/json';
  final body = {'limit': 10, 'orderBy': 'idEmployee', 'orderType': 'DESC'};
  final response = await dio.post(url, data: body);

  if (response.statusCode == 200) {
    print(response.statusCode);
    print(response.data);
    List<Map<String,dynamic>> data = response.data["data"]["data"];
    List<ListAlbum> albums = data.map((json) => ListAlbum.fromJson(json)).toList();

    
    return albums;
  } else {
    throw Exception('Failed!');
  }
}

继续将您的

FutureBuilder<ListAlbum>

编辑为

FutureBuilder<List<ListAlbum>>

并返回

Listview.builder

。有关如何使用的更多信息

Listview.builder

https://flutter.dev/docs/cookbook/lists/long-lists