我想知道是否有通过 SwiftUI 导出或共享文件的好方法。似乎没有办法包装 UIActivityViewController 并直接呈现它。我使用 UIViewControllerRepresentable 来包装 UIActivityViewController,如果我将它呈现在 SwiftUI Modal 中,它就会崩溃。
我能够创建一个通用的 UIViewController,然后从那里调用一个呈现 UIActivityViewController 的方法,但这需要大量的包装。
如果我们想使用 SwiftUI 从 Mac 进行共享,有没有办法包装 NSSharingServicePicker?
无论如何,如果有人有一个他们如何做到这一点的例子,我们将不胜感激。
您可以在任何地方定义此函数(最好在全局范围内):
@discardableResult
func share(
items: [Any],
excludedActivityTypes: [UIActivity.ActivityType]? = nil
) -> Bool {
guard let source = UIApplication.shared.windows.last?.rootViewController else {
return false
}
let vc = UIActivityViewController(
activityItems: items,
applicationActivities: nil
)
vc.excludedActivityTypes = excludedActivityTypes
vc.popoverPresentationController?.sourceView = source.view
source.present(vc, animated: true)
return true
}
您可以在按钮操作中或任何其他需要的地方使用此功能:
Button(action: {
share(items: ["This is some text"])
}) {
Text("Share")
}
我们可以直接从 View (SwiftUI) 调用 UIActivityViewController,无需使用
UIViewControllerRepresentable
。
import SwiftUI
enum Coordinator {
static func topViewController(_ viewController: UIViewController? = nil) -> UIViewController? {
let vc = viewController ?? UIApplication.shared.windows.first(where: { $0.isKeyWindow })?.rootViewController
if let navigationController = vc as? UINavigationController {
return topViewController(navigationController.topViewController)
} else if let tabBarController = vc as? UITabBarController {
return tabBarController.presentedViewController != nil ? topViewController(tabBarController.presentedViewController) : topViewController(tabBarController.selectedViewController)
} else if let presentedViewController = vc?.presentedViewController {
return topViewController(presentedViewController)
}
return vc
}
}
struct ActivityView: View {
var body: some View {
Button(action: {
self.shareApp()
}) {
Text("Share")
}
}
}
extension ActivityView {
func shareApp() {
let textToShare = "something..."
let activityViewController = UIActivityViewController(activityItems: [textToShare], applicationActivities: nil)
let viewController = Coordinator.topViewController()
activityViewController.popoverPresentationController?.sourceView = viewController?.view
viewController?.present(activityViewController, animated: true, completion: nil)
}
}
struct ActivityView_Previews: PreviewProvider {
static var previews: some View {
ActivityView()
}
}
这是预览:
希望能帮助别人!
编辑:删除了所有代码和对
UIButton
的引用。
感谢@Matteo_Pacini 回答这个问题,向我们展示了这项技术。与他的回答(和评论)一样,(1)这有点粗糙,(2)我不确定这就是苹果希望我们使用的方式
UIViewControllerRepresentable
,我真的希望他们提供更好的SwiftUI
( “SwiftierUI”?)在未来的测试版中替换。
我在
UIKit
中投入了大量工作,因为我希望它在 iPad 上看起来不错,而弹出窗口需要 sourceView
。真正的技巧是显示一个 (SwiftUI) View
,它在视图层次结构中获取 UIActivityViewController
并从 present
触发 UIKit
。
我的需求是呈现一个单一的图像来分享,所以事情都是朝着这个方向发展的。假设您有一个图像,存储为
@State
变量 - 在我的示例中,该图像称为 vermont.jpg,是的,对此进行了硬编码。
首先,创建一个 `UIViewController 类型的
UIKit
类来呈现共享弹出窗口:
class ActivityViewController : UIViewController {
var uiImage:UIImage!
@objc func shareImage() {
let vc = UIActivityViewController(activityItems: [uiImage!], applicationActivities: [])
vc.excludedActivityTypes = [
UIActivity.ActivityType.postToWeibo,
UIActivity.ActivityType.assignToContact,
UIActivity.ActivityType.addToReadingList,
UIActivity.ActivityType.postToVimeo,
UIActivity.ActivityType.postToTencentWeibo
]
present(vc,
animated: true,
completion: nil)
vc.popoverPresentationController?.sourceView = self.view
}
}
主要是;
UIViewController
才能present
事情。var uiImage:UIImage!
来设置 activityItems
。接下来,将其包装成
UIViewControllerRepresentable
:
struct SwiftUIActivityViewController : UIViewControllerRepresentable {
let activityViewController = ActivityViewController()
func makeUIViewController(context: Context) -> ActivityViewController {
activityViewController
}
func updateUIViewController(_ uiViewController: ActivityViewController, context: Context) {
//
}
func shareImage(uiImage: UIImage) {
activityViewController.uiImage = uiImage
activityViewController.shareImage()
}
}
唯一值得注意的两件事是:
ActivityViewController
将其返回到 ContentView
shareImage(uiImage:UIImage
) 来调用它。最后,你有
ContentView
:
struct ContentView : View {
let activityViewController = SwiftUIActivityViewController()
@State var uiImage = UIImage(named: "vermont.jpg")
var body: some View {
VStack {
Button(action: {
self.activityViewController.shareImage(uiImage: self.uiImage!)
}) {
ZStack {
Image(systemName:"square.and.arrow.up").renderingMode(.original).font(Font.title.weight(.regular))
activityViewController
}
}.frame(width: 60, height: 60).border(Color.black, width: 2, cornerRadius: 2)
Divider()
Image(uiImage: uiImage!)
}
}
}
请注意,
uiImage
有一些硬编码和(呃)强制展开,以及不必要的@State
的使用。这些之所以存在,是因为我计划使用“UIImagePickerController”来将它们结合在一起。
这里注意事项:
SwiftUIActivityViewController
,并使用 shareImage
作为按钮操作。UIViewControllerRepresentable
实际上也只是被视为 SwiftUI View
!将图像的名称更改为您项目中的名称,这应该可以工作。您将看到一个居中的 60x60 按钮,其下方有图像。
这里的大多数解决方案都忘记填充 iPad 上的共享表。
因此,如果您想让应用程序在此设备上不崩溃,您可以使用 此方法使用
popoverController
并添加您想要的 activityItems
作为参数。
import SwiftUI
/// Share button to populate on any SwiftUI view.
///
struct ShareButton: View {
/// Your items you want to share to the world.
///
let itemsToShare = ["https://itunes.apple.com/app/id1234"]
var body: some View {
Button(action: { showShareSheet(with: itemsToShare) }) {
Image(systemName: "square.and.arrow.up")
.font(.title2)
.foregroundColor(.blue)
}
}
}
extension View {
/// Show the classic Apple share sheet on iPhone and iPad.
///
func showShareSheet(with activityItems: [Any]) {
guard let source = UIApplication.shared.windows.last?.rootViewController else {
return
}
let activityVC = UIActivityViewController(
activityItems: activityItems,
applicationActivities: nil)
if let popoverController = activityVC.popoverPresentationController {
popoverController.sourceView = source.view
popoverController.sourceRect = CGRect(x: source.view.bounds.midX,
y: source.view.bounds.midY,
width: .zero, height: .zero)
popoverController.permittedArrowDirections = []
}
source.present(activityVC, animated: true)
}
}
看看 AlanQuatermain -s SwiftUIShareSheetDemo
简而言之,它看起来像这样:
@State private var showShareSheet = false
@State public var sharedItems : [Any] = []
Button(action: {
self.sharedItems = [UIImage(systemName: "house")!]
self.showShareSheet = true
}) {
Text("Share")
}.sheet(isPresented: $showShareSheet) {
ShareSheet(activityItems: self.sharedItems)
}
struct ShareSheet: UIViewControllerRepresentable {
typealias Callback = (_ activityType: UIActivity.ActivityType?, _ completed: Bool, _ returnedItems: [Any]?, _ error: Error?) -> Void
let activityItems: [Any]
let applicationActivities: [UIActivity]? = nil
let excludedActivityTypes: [UIActivity.ActivityType]? = nil
let callback: Callback? = nil
func makeUIViewController(context: Context) -> UIActivityViewController {
let controller = UIActivityViewController(
activityItems: activityItems,
applicationActivities: applicationActivities)
controller.excludedActivityTypes = excludedActivityTypes
controller.completionWithItemsHandler = callback
return controller
}
func updateUIViewController(_ uiViewController: UIActivityViewController, context: Context) {
// nothing to do here
}
}
从 iOS 16 开始,您可以使用 ShareLink:
ShareLink(item: "http://www.myappurl.com") {
Label("Share app", systemImage: "square.and.arrow.up")
}
或者只是:
ShareLink(item: "http://www.myappurl.com")