如何在Python中将“ n”行转换为.csv？

Question

数据集（提取2个单独的项目，n每个项目6列）：

1
No. of A
600
No. of B
2
No. of C

6
No. of A
500
No. of B
4
No. of C

...

使用Python，最好的方法是将上面的内容转换并输出为如下所示的.csv文件？

1,No. of A,600,No. of B,2,No. of C
6,No. of A,500,No. of B,4,No. of C
...

感谢所有建议！

修改答案

body = """
1
No. of A
600
No. of B
2
No. of C
6
No. of A
500
No. of B
4
No. of C
7
No. of A
501
No. of B
5
No. of C
"""

temp_body = body.strip().split("\n")
parsed_body = [temp_body[(0 + i - 6):i] for i in range(6, len(temp_body) + 1, 6)]                                  

import pandas as pd

df =  pd.DataFrame(parsed_body)

df.to_csv('output.csv', sep=',', header=None, index=None)

结果

Answer 1

假设\n\n分隔了2个不同的行，然后您可以这样尝试：

 In [1]: body = """ 
    ...: 1 
    ...: No. of A 
    ...: 600 
    ...: No. of B 
    ...: 2 
    ...: No. of C 
    ...:  
    ...: 6 
    ...: No. of A 
    ...: 500 
    ...: No. of B 
    ...: 4 
    ...: No. of C 
    ...: """                                                                                                                

 In [2]: parsed_body = [i.strip().split("\n") for i in body.split("\n\n")]                                                  

 In [3]: parsed_body                                                                                                        
 Out[4]: 
 [['1', 'No. of A', '600', 'No. of B', '2', 'No. of C'],
  ['6', 'No. of A', '500', 'No. of B', '4', 'No. of C']]

一旦获得列表，就可以在Python中使用csv模块使用csvwriter，并将其写为csv

如果\ n \ n不是我们的情况，并且是连续的，那么您可以尝试类似的方法（有点hack，但也许您可以提出更好的方法）：

In [43]: body = """ 
    ...: 1 
    ...: No. of A 
    ...: 600 
    ...: No. of B 
    ...: 2 
    ...: No. of C 
    ...: 6 
    ...: No. of A 
    ...: 500 
    ...: No. of B 
    ...: 4 
    ...: No. of C 
    ...: 22 
    ...: No. of Q 
    ...: 500 
    ...: No. of R 
    ...: 4 
    ...: No. of S 
    ...: """                                                                                                                

In [44]: temp_body = body.strip().split("\n")                                                                               

In [45]: parsed_body = [temp_body[(0 + i - 6):i] for i in range(6, len(temp_body) + 1, 6)]                                  

In [46]: parsed_body                                                                                                        
Out[46]: 
[['1', 'No. of A', '600', 'No. of B', '2', 'No. of C'],
 ['6', 'No. of A', '500', 'No. of B', '4', 'No. of C'],
 ['22', 'No. of Q', '500', 'No. of R', '4', 'No. of S']]

Answer 2

假设您的数据一致且干净，则可以在双换行符处拆分数据。然后为每个项目用逗号替换换行符：

data = '''1
No. of A
600
No. of B
2
No. of C

6
No. of A
500
No. of B
4
No. of C'''

items = [item.replace('\n', ',') for item in data.split('\n\n')]
print('\n'.join(items))
# 1,No. of A,600,No. of B,2,No. of C
# 6,No. of A,500,No. of B,4,No. of C