带有PA0按钮的STM32F303VCT6外部中断将不会切换LED

Question

我想使用连接到PA0的按钮作为外部中断，以在按下按钮时切换PE14上的LED。但是，调用configure_PA0函数似乎无效。

我在while循环中做了一个简单的闪烁指令以进行测试，结果当我调用configure_PA0时，LED一直保持点亮状态。

如果不调用它，LED会闪烁得很好，所以我认为此功能一定有问题。

#include "stm32f30x.h"

void delay(volatile uint32_t count){
    while(count > 0 )
        count--;
}

void init_LED(){ //init led on PE14
    RCC_AHBPeriphClockCmd(RCC_AHBPeriph_GPIOE, ENABLE);
        GPIO_InitTypeDef GPIO_InitStructure;
        GPIO_InitStructure.GPIO_Pin = GPIO_Pin_14;
        GPIO_InitStructure.GPIO_OType = GPIO_OType_PP;
        GPIO_InitStructure.GPIO_Mode = GPIO_Mode_OUT;
        GPIO_InitStructure.GPIO_Speed = GPIO_Speed_50MHz;
        GPIO_InitStructure.GPIO_PuPd = GPIO_PuPd_NOPULL;
        GPIO_Init(GPIOE,&GPIO_InitStructure);
}
void configure_PA0(void) {

    GPIO_InitTypeDef GPIO_InitStruct;
    EXTI_InitTypeDef EXTI_InitStruct;
    NVIC_InitTypeDef NVIC_InitStruct;

    RCC_AHBPeriphClockCmd(RCC_AHBPeriph_GPIOA, ENABLE);
    RCC_APB2PeriphClockCmd(RCC_APB2Periph_SYSCFG, ENABLE);
//PA0 as button init
    GPIO_InitStruct.GPIO_Mode = GPIO_Mode_IN;
    GPIO_InitStruct.GPIO_OType = GPIO_OType_PP;
    GPIO_InitStruct.GPIO_Pin = GPIO_Pin_0;
    GPIO_InitStruct.GPIO_PuPd = GPIO_PuPd_UP;
    GPIO_InitStruct.GPIO_Speed = GPIO_Speed_50MHz;
    GPIO_Init(GPIOA, &GPIO_InitStruct);

//EXTI init
    SYSCFG_EXTILineConfig(EXTI_PortSourceGPIOA, EXTI_PinSource0);
    EXTI_InitStruct.EXTI_Line = EXTI_Line0;
    EXTI_InitStruct.EXTI_LineCmd = ENABLE;
    EXTI_InitStruct.EXTI_Mode = EXTI_Mode_Interrupt;
    EXTI_InitStruct.EXTI_Trigger = EXTI_Trigger_Rising;
    EXTI_Init(&EXTI_InitStruct);

//NVIC init
    NVIC_InitStruct.NVIC_IRQChannel = EXTI0_IRQn;
    NVIC_InitStruct.NVIC_IRQChannelPreemptionPriority = 0x00;
    NVIC_InitStruct.NVIC_IRQChannelSubPriority = 0x00;
    NVIC_InitStruct.NVIC_IRQChannelCmd = ENABLE;
    NVIC_Init(&NVIC_InitStruct);
}


void toggle_PE14(){
    if(GPIO_ReadOutputDataBit(GPIOE,GPIO_Pin_14) == 0)
        GPIO_SetBits(GPIOE,GPIO_Pin_14);
    else
        GPIO_ResetBits(GPIOE,GPIO_Pin_14);
}

//handle pa0 interrupt
void EXTI0_IRQHandler(void) {
    if(EXTI_GetITStatus(EXTI_Line0) != RESET){
        toggle_PE14();

        EXTI_ClearITPendingBit(EXTI_Line0);
    }
}


int main(void) {

    init_LED();
    configure_PA0();

    while (1) {
        delay(400);
    }

    return 0;
}

更新我通过将处理程序定义放在extern "C" { .. }中来解决此问题。显然，如果您在C++中进行编码，则必须这样做。

我想使用连接到PA0的按钮作为外部中断，以在按下按钮时切换PE14上的LED。但是，调用configure_PA0函数似乎不起作用。我做了一个简单的闪烁...

Answer 1

更新...