我在使用FirebaseUI时遇到问题。问题是,它在启动时启动了电子邮件登录流程,而没有单击任何东西。我希望它显示不同的登录选项,但是它会继续启动电子邮件登录流程。我希望它显示此内容:
但是,只要应用程序启动,它就直接进入电子邮件登录流程,而无需单击任何东西。我从来没有选择Facebook或Google的选项
这是我的LoginActivty
public class LoginActivity extends AppCompatActivity {
private static final int MY_REQUEST_CODE = 7117;
private FirebaseAuth mAuth;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mAuth = FirebaseAuth.getInstance();
setContentView(R.layout.activity_login);
showSignInOptions();
}
@Override
protected void onStart() {
super.onStart();
FirebaseUser currentUser = mAuth.getCurrentUser();
if (currentUser != null) {
startActivity(new Intent(LoginActivity.this, MainActivity.class));
}
else {
Toast.makeText(this, "", Toast.LENGTH_SHORT).show();
}
}
public void showSignInOptions() {
AuthMethodPickerLayout loginLayout = new AuthMethodPickerLayout
.Builder(R.layout.activity_login)
.setEmailButtonId(R.id.email_button)
.setFacebookButtonId(R.id.facebook_button)
.setGoogleButtonId(R.id.google_button)
.build();
startActivityForResult(
AuthUI.getInstance().createSignInIntentBuilder()
.setTheme(R.style.AppTheme)
.setAuthMethodPickerLayout(loginLayout)
.build(), MY_REQUEST_CODE
);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == MY_REQUEST_CODE) {
IdpResponse response = IdpResponse.fromResultIntent(data);
if (resultCode == RESULT_OK) {
startActivity(new Intent(LoginActivity.this, MainActivity.class));
FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
Toast.makeText(this, "Welcome " + user.getDisplayName(), Toast.LENGTH_SHORT).show();
}
else {
Toast.makeText(this, "" + response.getError().getMessage(), Toast.LENGTH_SHORT).show();
}
}
}
我在代码中看不到任何应该启动电子邮件流的地方。请帮我。在此先感谢
这是启动登录流程的代码:
startActivityForResult(
AuthUI.getInstance().createSignInIntentBuilder()
.setTheme(R.style.AppTheme)
.setAuthMethodPickerLayout(loginLayout)
.build(), MY_REQUEST_CODE
);
startActivityForResult
完全按照其说的做,它启动了一个活动,在这种情况下,它被告知启动Firebase UI活动。由于您是在onCreate期间调用它的,因此当前活动永远对用户不可见。
已解决。我只需要使用
setAvailableProviders();
对于我的SignInIntentBuilder();
我新的LoginActivity的代码:
public class LoginActivity extends AppCompatActivity {
private static final int MY_REQUEST_CODE = 7117;
private FirebaseAuth mAuth;
@Override
protected void onStart(){
super.onStart();
FirebaseUser currentUser = mAuth.getCurrentUser();
if (currentUser != null) {
startActivity(new Intent(LoginActivity.this, MainActivity.class));
Toast.makeText(this, "Welcome back " + currentUser.getDisplayName(), Toast.LENGTH_SHORT).show();
}
else {
Toast.makeText(this, "Please log in", Toast.LENGTH_SHORT).show();
}
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
mAuth = FirebaseAuth.getInstance();
showSignInOptions();
}
private void showSignInOptions() {
List<AuthUI.IdpConfig> providers = new ArrayList<>();
providers.add(new AuthUI.IdpConfig.EmailBuilder().build());
providers.add(new AuthUI.IdpConfig.FacebookBuilder().build());
providers.add(new AuthUI.IdpConfig.GoogleBuilder().build());
AuthUI.SignInIntentBuilder builder = AuthUI.getInstance().createSignInIntentBuilder();
AuthMethodPickerLayout loginLayout = new AuthMethodPickerLayout
.Builder(R.layout.activity_login)
.setEmailButtonId(R.id.email_button)
.setFacebookButtonId(R.id.facebook_button)
.setGoogleButtonId(R.id.google_button)
.build();
startActivityForResult(
builder.setAuthMethodPickerLayout(loginLayout)
.setAvailableProviders(providers)
.setTheme(R.style.AppTheme)
.setIsSmartLockEnabled(false)
.build(), MY_REQUEST_CODE);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == MY_REQUEST_CODE) {
IdpResponse response = IdpResponse.fromResultIntent(data);
if (resultCode == RESULT_OK) {
FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
Toast.makeText(this, "Welcome " + user.getDisplayName(), Toast.LENGTH_SHORT).show();
}
else {
Toast.makeText(this, "" + response.getError().getMessage(), Toast.LENGTH_SHORT).show();
}
}
}
发现了一个相关的stackoverflow问题here