我想保持联系的地址之一在这里:
到目前为止我所做的:
from urllib.request import Request, urlopen
url = 'https://etherscan.io/token/0xd6a55c63865affd67e2fb9f284f87b7a9e5ff3bd?a=0x94f52b6520804eced0accad7ccb93c73523af089'
req = Request(url, headers={'User-Agent': 'XYZ/3.0'}) # I got this line from another post since "uClient = uReq(URL)" and "page_html = uClient.read()" would not work (I beleive that etherscan is attemption to block webscraping or something?)
response = urlopen(req, timeout=20).read()
response_close = urlopen(req, timeout=20).close()
page_soup = soup(response, "html.parser")
Transfers_info_table_1 = page_soup.find("div", {"class": "table-responsive"})
print(Transfers_info_table_1)
有趣的是,当我运行它时,得到以下输出:
<div class="table-responsive" style="visibility:hidden;"> <iframe frameborder="0" id="tokentxnsiframe" scrolling="no" src="" style="width: 100px; height: 600px; min-width: 100%;"></iframe> </div>
我原本希望获得整个转帐表的输出。我在这里错了吗?
iframe
内部。复制iframe的src
值,然后使用请求获取该url的内容。from urllib.request import Request, urlopen
from bs4 import BeautifulSoup as soup
import pandas as pd
url = 'https://etherscan.io/token/generic-tokentxns2?m=normal&contractAddress=0xd6a55c63865affd67e2fb9f284f87b7a9e5ff3bd&a=0xd071f6e384cf271282fc37eb40456332307bb8af'
req = Request(url, headers={'User-Agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36'}) # I got this line from another post since "uClient = uReq(URL)" and "page_html = uClient.read()" would not work (I beleive that etherscan is attemption to block webscraping or something?)
response = urlopen(req, timeout=20).read()
response_close = urlopen(req, timeout=20).close()
page_soup = soup(response, "html.parser")
Transfers_info_table_1 = page_soup.find("table", {"class": "table table-md-text-normal table-hover mb-4"})
df=pd.read_html(str(Transfers_info_table_1))[0]
df.to_csv("TransferTable.csv",index=False)
生成的csv。