EditText中每行的单词数不足

问题描述 投票:0回答:1

我尝试在EditText中将每行动态单词放置到位,但是当我按键盘的新行时,系统显示1个单词。


我的EditText

          <EditText
                android:id="@+id/note_content_edittext"
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:background="@color/white"
                android:focusable="true"
                android:gravity="top|start"
                android:textSize="17sp"
                android:isScrollContainer="true"
                android:textAlignment="textStart"
                android:inputType="textMultiLine"/>

事件监听器:

          note_content_edittext.addTextChangedListener(new TextWatcher() {
                @Override
                public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

                @Override
                public void onTextChanged(CharSequence s, int start, int before, int count) {
                    wordPerLineNumber();
                }

                @Override
                public void afterTextChanged(Editable s) {}
            });

和wordPerLineNumber函数:

     private void wordPerLineNumber() {
        final String noteText = note_content_edittext.getText().toString();
        Layout layout = note_content_edittext.getLayout();

        int noteLineNumber = layout.getLineCount();
        int endIndex, wordNumberPerLine;

        StringBuilder text = new StringBuilder();


        for (int i = 0, startIndex = 0; i < noteLineNumber; i++) {
            endIndex = layout.getLineVisibleEnd(i);
            wordNumberPerLine = noteText.subSequence(startIndex, endIndex).toString().split(" ").length;

            text.append(wordNumberPerLine).append("\n");
            startIndex = endIndex;
        }

        line_number_textview.setText(text.toString()); // I show the result in a textView
    }

[我认为我的问题可能是由于当我在键盘上按新行而添加了“ \ r”,但我不知道该如何解决。

java android android-studio word
1个回答
0
投票

您走在正确的轨道上。您可以从结果字符串中删除所有换行符\n。只需将.replace("\n", "")添加到wordPerLineNumber()方法即可。

最终代码:

private void wordPerLineNumber() {
    final String noteText = editText.getText().toString();
    Layout layout = editText.getLayout();

    int noteLineNumber = layout.getLineCount();
    int endIndex, wordNumberPerLine;

    StringBuilder text = new StringBuilder();

    for (int i = 0, startIndex = 0; i < noteLineNumber; i++) {
        endIndex = layout.getLineVisibleEnd(i);
        String[] temp = noteText.subSequence(startIndex, endIndex).toString().replaceAll("\n", "").split(" ");
        wordNumberPerLine = temp.length;
        if (temp[0].length() == 0)
            wordNumberPerLine = 0;
        text.append(wordNumberPerLine).append("\n");
        startIndex = endIndex;
    }

    textView.setText(text.toString());// I show the result in a textView
}

此外,请记住,"".split(" ")返回1,所以如果需要,您可能需要检查一个空字符串

if (str.length() == 0)
    wordNumberPerLine = 0
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