FileHelper读取流式传输并使用web api下载

问题描述 投票:2回答:3

我有一个对象列表,我想通过Web Api下载为csv文件。但是当我用Swagger测试时,我没有下载csv。我究竟做错了什么? DailyReportContent包含2个对象。

到目前为止这是我的代码:

public IActionResult GetDailyReport(DateTime invoiceDate)
{
    var dailyReportContent = new List<DailyReportModel>().....

    // create csv file
    var engine = new FileHelperEngine<DailyReportModel>
    {
        HeaderText = "headers.."
    };

    using (var stream = new MemoryStream())
    using (var streamWriter = new StreamWriter(stream))
    {
        engine.WriteStream(streamWriter, dailyReportContent);

        var result = new HttpResponseMessage(HttpStatusCode.OK);
        result.Content = new StreamContent(stream);
        result.Content.Headers.ContentType = new MediaTypeHeaderValue("text/csv");
        result.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment") { FileName = "DailyReports.csv" };

        return Ok(result);
    }
}

这是Swagger的回应:

{
  "version": {
    "major": 1,
    "minor": 1,
    "build": -1,
    "revision": -1,
    "majorRevision": -1,
    "minorRevision": -1
  },
  "content": {
    "headers": [
      {
        "key": "Content-Type",
        "value": [
          "text/csv"
        ]
      },
      {
        "key": "Content-Disposition",
        "value": [
          "attachment; filename=DailyReports.csv"
        ]
      }
    ]
  },
  "statusCode": 200,
  "reasonPhrase": "OK",
  "headers": [],
  "requestMessage": null,
  "isSuccessStatusCode": true
}

编辑:即使我添加这个:

 stream.Flush();
 streamWriter.Flush();

 var reader = new StreamReader(stream);
 var readResult = reader.ReadToEnd();

readResult是空的。所以我想在编写流时会出现问题?

c# asp.net-web-api filehelpers
3个回答
0
投票

我想你需要

return result;

返回“Ok(<object>)”将返回包含该对象的响应消息。 您已经创建了响应消息并指定了所有内容。 所以我认为你正在返回一个OK响应,包含另一个OK响应消息。


0
投票

修正如下:

var csvContent = LoadcsvContent();

var engine = new FileHelperEngine<DailyReportModel>
{
    HeaderText = "......."
};

var stream = new MemoryStream();
TextWriter streamWriter = new StreamWriter(stream);
engine.WriteStream(streamWriter, csvContent);

streamWriter.Flush();
stream.Seek(0, SeekOrigin.Begin);

return File(await stream, "text/csv", $"Report_{invoiceDate:yyyyMMdd}.csv");

现在就像一个魅力。 Swagger输出:

enter image description here


0
投票

在ASP.Net Core中我们有qazxsw poi

返回我们需要的类型的文件,在我的情况下为.msi包我使用return File(ret, "application/octet-stream", fileName);你可以在控制器级别指定返回类型为.CSV或在"application/octet-stream"类的WebApiConfig类中指定返回类型

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