我定义了一个随机数,我想检查它是否是一个回文java

问题描述 投票:0回答:3
import java.util.Random;

public class Loop6 {
    public static void main(String[] args) {

        Random number = new Random();
        int value = number.nextInt(1000);
        System.out.println("random number : " + " " + value);

        int rev = 0;
        int dig;

        while (value > 0) {
            dig = value % 10;
            rev = rev * 10;
            rev = rev + dig;
            value = value / 10;
        }
        System.out.println("rev is : " + "" + rev);
        if(value==rev) {
            System.out.println("Palindrome");

        }

    }
}
java palindrome
3个回答
0
投票

你的代码几乎没问题,只是你要更新的初始随机数不是你想要的。为了使代码保持最小变化,我建议您添加一个新变量并将其与反向算法的结果进行比较。

import java.util.Random;

public class Loop6 {
    public static void main(String[] args) {

        Random number = new Random();
        int randomNumber = number.nextInt(1000);  // introduce the initial variable
        int value = randomNumber;  // introduce the variable that will be updated
        System.out.println("random number : " + " " + value);

        int rev = 0;
        int dig;

        while (value > 0) {
            dig = value % 10;
            rev = rev * 10;
            rev = rev + dig;
            value = value / 10;
        }
        System.out.println("rev is : " + "" + rev);
        if (randomNumber == rev) {  // compare the initial variable and the reverse result
            System.out.println("Palindrome");

        }

    }
}

1
投票

Java有内置的方法来反转字符串。

String originalValue = value + "";
StringBuilder stringBuilder = new StringBuilder(originalValue);
String reverseValue = stringBuilder.reverse().toString();

if (originalValue.equals(reverseValue)) System.out.println("Palindrome");

0
投票

方案:

public class Test {

    public static void main(String[] args) {
        Random number = new Random();
        int value = number.nextInt(1000);
        System.out.println("Original number : " + " " + value);
        int tmp = value;
        int result = 0;
        while (tmp != 0) {
            result = result * 10 + (tmp % 10);
            tmp = tmp / 10;
        }
        System.out.println("Reversed Number : " + " " + result);
        if (result != value) {
            System.out.println("Not Palindrome");
        } else {
            System.out.println("Palindrome");
        }

    }

}

谢谢 :)

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