检查数组中的多个对象，并比较对象中的某些属性何时满足条件

Question

我的问题的一个例子是这样的：

const costsArray = [
  {Id: 0, type: 'store', location: ['101, 102, 103']},
  {Id: 1, type: 'cost', location: ['109, 110, 111'], value: 460},
  {Id: 2, type: 'cost', location: ['109, 110, 111'], value: 60000},
  {Id: 3, type: 'item', location: ['109, 110, 111'], value: 460},
  {Id: 4, type: 'cost', location: ['109, 110, 111'], value: 461}
]

这里有多个彼此相似的属性。我要实现的目标是：比较所有这些对象，如果任何对象的类型为'cost'and具有相同的'location'属性，则console.log表示ID：1、2、4具有不同的值。

到目前为止，我不确定，虽然不确定方向是否正确

costsArray.forEach((x: any) => {
   if(x.type.name === "cost" && x.location.id === })

Answer 1

您的意思是这样的？

const costsArray = [
  {Id: 0, type: 'store', location: '101, 102, 103'},
  {Id: 1, type: 'cost', location: '109, 110, 111', value: 460},
  {Id: 2, type: 'cost', location: '109, 110, 111', value: 60000},
  {Id: 3, type: 'item', location: '109, 110, 111', value: 460},
  {Id: 4, type: 'cost', location: '109, 110, 111', value: 461}
];

let costLocations = {};
for (let c of costsArray) {
  if (c.type = 'cost') {
    (costLocations[c.location] = costLocations[c.location] || []).push(c.Id);  
  }
}

for (let key in costLocations) {
  if (costLocations[key].length > 1) {
      console.log(costLocations[key] + " have different values")  
  }
}

Answer 2

const costsArray = [
  {Id: 0, type: 'store', location: '101, 102, 103'},
  {Id: 1, type: 'cost', location: '109, 110, 111', value: 460},
  {Id: 2, type: 'cost', location: '109, 110, 111', value: 60000},
  {Id: 3, type: 'item', location: '109, 110, 111', value: 460},
  {Id: 4, type: 'cost', location: '109, 110, 111', value: 461}
];

console.log(
  /* only get items whose type is 'cost' */
  costsArray.filter(cost => cost.type === 'cost')
            /* find items whose value unique */
            .filter((item, i, filteredArray) => filteredArray.find(it => it.value === item.value && it.Id !== item.Id) === undefined)
            /* select only the value from that item */
            .map(item => item.Id)
);