Spring JPA Base Repository

问题描述 投票:0回答:1

我创建了一个自定义存储库来覆盖持久性方法,并尝试按照spring docs中的描述将其连接起来。我没有收到错误,所有实体和存储库都在启动时找到,当我调用repo.saveAll(实体)时,持久性正常。但是,我的自定义代码永远不会被调用。我已经添加了日志语句,甚至在我的代码中抛出了RuntimeExceptions,只是为了查看它是否正在被执行,但它肯定会被忽略。我错过了什么步骤?

@Configuration
@Profile("test")
@EnableJpaRepositories(repositoryBaseClass = SetClientInfoRepositoryImpl.class,
        basePackages = {"gov.penndot.hwy.apras.common.repository" }, 
        entityManagerFactoryRef = "serviceEntityManagerFactory", 
        transactionManagerRef = "serviceTransactionManager")
public class TestDatabaseConfig {

    @Bean(name = "serviceDataSource")
    public DataSource dataSource() {
        DriverManagerDataSource dataSource = new DriverManagerDataSource();
        dataSource.setDriverClassName("org.h2.Driver");
        dataSource.setUrl("jdbc:h2:mem:db;DB_CLOSE_DELAY=-1");
        dataSource.setUsername("sa");
        dataSource.setPassword("sa");

        return dataSource;
    }

    @Bean
    public EntityManagerFactoryBuilder entityManagerFactoryBuilder() {
        return new EntityManagerFactoryBuilder(new HibernateJpaVendorAdapter(), new HashMap<String, Object>(), null);
    }

    @Bean(name = "serviceEntityManagerFactory")
    public LocalContainerEntityManagerFactoryBean serviceEntityManagerFactory(EntityManagerFactoryBuilder builder,
            @Qualifier("serviceDataSource") DataSource dataSource) {

        return builder
                .dataSource(dataSource)
                .packages("stuff")
                .persistenceUnit("service")
                .build();
    }

    @Bean(name = "serviceTransactionManager")
    public PlatformTransactionManager transactionManager(
            @Qualifier("serviceEntityManagerFactory") EntityManagerFactory serviceEntityManagerFactory) {
        return new JpaTransactionManager(serviceEntityManagerFactory);
    }

库:

@NoRepositoryBean
    public class SetClientInfoRepositoryImpl<T, ID extends Serializable> extends SimpleJpaRepository<T, ID> {
        private static final Logger log = LoggerFactory.getLogger(SetClientInfoRepositoryImpl.class);
        private final EntityManager em;

        public SetClientInfoRepositoryImpl(JpaEntityInformation<T, ID> entityInformation, EntityManager entityManager) {
            super(entityInformation, entityManager);
            this.em = entityManager;
        }

        @Transactional
        @Override
        public <S extends T> S save(S entity) {
            setClientInfo();
            return super.save(entity);
        }

        @Transactional
        @Override
        public void deleteById(ID id) {
            setClientInfo();
            super.deleteById(id);
        }

        @Transactional
        @Override
        public void delete(T entity) {
            setClientInfo();
            super.delete(entity);
        }

        @Transactional
        @Override
        public void deleteAll(Iterable<? extends T> entities) {
            setClientInfo();
            super.deleteAll(entities);
        }

        @Transactional
        @Override
        public void deleteInBatch(Iterable<T> entities) {
            setClientInfo();
            super.deleteInBatch(entities);
        }

        @Transactional
        @Override
        public void deleteAll() {
            setClientInfo();
            super.deleteAll();
        }

        @Transactional
        @Override
        public void deleteAllInBatch() {
            setClientInfo();
            super.deleteAllInBatch();
        }

        @Transactional
        @Override
        public <S extends T> S saveAndFlush(S entity) {
            setClientInfo();
            return super.saveAndFlush(entity);
        }

        @Transactional
        @Override
        public <S extends T> List<S> saveAll(Iterable<S> entities) {
            setClientInfo();
            super.saveAll(entities);
            throw new RuntimeException("foo");
        }

        private void setClientInfo() {
            log.debug("Entering setClientInfo method");
            [stuff]
        }
    }
java spring spring-data-jpa jpa-2.0
1个回答
0
投票

好吧,这是一个非常绝望的想法,但它值得一试......

创建自定义存储库接口:

public interface SetClientInfoRepository<T, ID> extends JpaRepository<T, ID> {
}

通过自定义基本存储库实现此存储库接口:

public class SetClientInfoRepositoryImpl<T, ID extends Serializable> extends SimpleJpaRepository<T, ID> implements SetClientInfoRepository<T, ID> {
}

...最后通过存储库接口而不是JpaRepository扩展此接口

通过这种方式,Spring必须从您的实现中创建存储库代理,因为它不能使用其他类。此外,如果由于任何原因无法创建存储库,您将在启动期间获得更多信息性异常。

使用自定义存储库接口本身并不是件坏事,因为您总是很有可能希望稍后向存储库添加一些常用的自定义方法,然后它就会派上用场。

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