Android：无需点击即可在Listview上设置焦点突出显示

Question

我正在尝试使首选项目突出显示或成为焦点而不点击它。我已经可以从第一个项目的ListView适配器获取数据而不单击它。请帮帮我谢谢

这是Listview的代码

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="horizontal"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:weightSum="5"
android:padding="5dp"
android:layout_marginTop="2dp"
>
<TextView
    android:layout_width="match_parent"
    android:layout_height="80dp"
    android:textColor="#ffffff"
    android:textSize="25sp"
    android:text="1"
    android:id="@+id/lblproid"
    android:layout_marginLeft="15dp"
    android:editable="false" />

<TextView
    android:layout_width="match_parent"
    android:layout_height="80dp"
    android:textColor="#ffffff"
    android:textSize="25sp"
    android:text="1"
    android:id="@+id/lblproid1"
    android:layout_marginLeft="15dp"
    android:editable="false" />


</LinearLayout>

这用于填充ListView

 public class Onload extends AsyncTask<String, String, String> {

    List<Map<String, String>> prolist  = new ArrayList<Map<String, String>>();
    String z = "";
    Boolean isSuccess = false;

    @Override
    protected void onPreExecute() {
        pbbar.setVisibility(View.VISIBLE);
    }

    @Override
    protected void onPostExecute(String r) {
    if(isSuccess=true) {
            //display customer name
            pbbar.setVisibility(View.GONE);
            //Toast.makeText(getApplicationContext(), r, Toast.LENGTH_SHORT).show();
            String[] from = {"A", "B", "C"};
            int[] views = { R.id.lblproid, R.id.lblproid1};
            final SimpleAdapter ADA = new SimpleAdapter(workingStation.this,
                    prolist, R.layout.activity_lsttemplate, from,
                    views);
            lstpro.setAdapter(ADA);
            lstpro.setSelection(0);
            lstpro.setItemChecked(0,true);
            lstpro.setSelector(R.drawable.selector_color);
        try{
            HashMap<String, Object> obj = (HashMap<String, Object>) ADA.getItem(0);
            String userName = (String) obj.get("A");
            String c_id = (String) obj.get("C");
            edtUname.setText(userName);
            edtUserID2.setText(c_id);

        }catch (Exception e){
            Check onLOadquery = new Check();
            onLOadquery.execute("");

        }

     }


    }

    @Override
    protected String doInBackground(String... params) {

        try {
            Connection con = connectionClass.CONN();
            if (con == null) {
                z = "Error in connection with SQL server!!!!";
            } else {
                SharedPreferences pref = getSharedPreferences("MyPrefs", Context.MODE_PRIVATE);
                String win_name = pref.getString("window_number", "");
                String userName = pref.getString("username", "");
                String query = "SELECT customer_name, customer_id, customer_transaction from customer_process where customer_window = '" + win_name + "' and customer_status = 'Pending' ";
                Statement ps = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_READ_ONLY);
                ResultSet rs = ps.executeQuery(query);
                    ArrayList<String> data = new ArrayList<String>();
                    while (rs.next()) {
                        Map<String, String> datanum = new HashMap<String, String>();
                        datanum.put("A", rs.getString("customer_name"));
                        datanum.put("B", rs.getString("customer_transaction"));
                        datanum.put("C", rs.getString("customer_id"));
                        prolist.add(datanum);
                    }
                if(rs.last()){
                    Integer count = rs.getRow();
                    rs.beforeFirst();
                   if(count == 0){
                       isSuccess = false;


                   }else {
                       isSuccess = true;

                   }
                }

                //Toast.makeText(getApplicationContext(), "Count : "+count, Toast.LENGTH_SHORT).show();

                z = "Success";


            }

        } catch (Exception ex) {
            isSuccess = false;
        }
        return z;
    }
} // end Onload

还有我的Selector_color.xml

<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="@color/gray" android:state_pressed="true"/>
<item android:drawable="@color/gray" android:state_selected="true"/>
<item android:drawable="@color/gray" android:state_activated="true"/>
</selector>

Answer 1

这将做lv.setItemChecked(position, true);的工作

position是指您想要突出显示的行号，该行被选中但不可见。现在要使其可见，您需要在Arrayadapter中传递激活的布局构造函数。 R.layout.simple_list_item_activated_2

像这样：

ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
            android.R.layout.simple_list_item_activated_2, android.R.id.text1, myList);

如果你正在使用自定义ArrayAdapter，那么请参考这个帖子，它在那里有明确的解释。 Programmatically select item ListView in Android