打印服务器端响应[PHP]

Question

使用PayPal智能按钮集成，我遇到了一个问题，例如：

1。客户按下按钮，批准交易，并被重定向回成功页面。

2。批准后，会将订单ID发送到我的服务器（贝宝提供的php文件）https://developer.paypal.com/docs/checkout/integrate/#6-verify-the-transaction

此时，我需要在服务器上打印从getOrder函数获得的响应。我怎样才能做到这一点？我只能在客户端接收数据，我应该在getOrder之后创建一个POST请求，以将其实际打印到客户端进行测试？

（（已安装SDK）

对于Web开发还是新手，也许我缺少关键信息。

服务器端代码；

<?php

namespace Sample;

require __DIR__ . '/vendor/autoload.php';
//1. Import the PayPal SDK client that was created in `Set up Server-Side SDK`.
use Sample\PayPalClient;
use PayPalCheckoutSdk\Orders\OrdersGetRequest;

$data = json_decode(file_get_contents('php://input'), true);

class GetOrder
{
  // 2. Set up your server to receive a call from the client
  /**
   *You can use this function to retrieve an order by passing order ID as an argument.
   */
  public static function getOrder($orderId)
  {
    // 3. Call PayPal to get the transaction details
    $client = PayPalClient::client();
    $response = $client->execute(new OrdersGetRequest($orderId));
    /**
     *Enable the following line to print complete response as JSON.
     */
    print json_encode($response->result);
    print "Status Code: {$response->statusCode}\n";
    print "Status: {$response->result->status}\n";
    print "Order ID: {$response->result->id}\n";
    print "Intent: {$response->result->intent}\n";
    print "Links:\n";
    foreach ($response->result->links as $link) {
      print "\t{$link->rel}: {$link->href}\tCall Type: {$link->method}\n";
    }
    // 4. Save the transaction in your database. Implement logic to save transaction to your database for future reference.
    print "Gross Amount: {$response->result->purchase_units[0]->amount->currency_code} {$response->result->purchase_units[0]->amount->value}\n";

    // To print the whole response body, uncomment the following line
    echo json_encode($response->result, JSON_PRETTY_PRINT);
  }
}

/**
 *This driver function invokes the getOrder function to retrieve
 *sample order details.
 *
 *To get the correct order ID, this sample uses createOrder to create a new order
 *and then uses the newly-created order ID with GetOrder.
 */
if (!count(debug_backtrace())) {
  GetOrder::getOrder($data['orderID'], true);
}

客户端；

<script>
    paypal.Buttons({
        createOrder: function(data, actions) {
            return actions.order.create({
                purchase_units: [{
                    amount: {
                        value: '0.01'
                    }
                }]
            })
        },
        onApprove: function(data, actions) {
            return actions.order.capture().then(function(details) {
                alert('Transaction completed by ' + details.payer.name.given_name);

                console.log(data.orderID);
                // Call your server to save the transaction
                return fetch('server.php', {
                    method: 'post',
                    headers: {
                        'content-type': 'application/json',
                    },
                    body: JSON.stringify({
                        orderID: data.orderID
                    })
                }).then(function(res){
                    if(!res.ok){
                        throw new Error('Bad response from server.php');
                    }

                    window.location('succes.php');
                });
            });
        },
        onError: function(data, actions){
            window.location('error.php');
        }
}).render('#paypal-button-container');
</script>

Answer 1

在服务器端，您已经有：

echo json_encode($response->result, JSON_PRETTY_PRINT);

在此之前，您可能需要注释掉“打印”行，因为它们是多余的。

因此，正在返回数据。您想打印出来或对其进行处理。现在添加一个“ console.log”。：

            return fetch('server.php', {
                method: 'post',
                headers: {
                    'content-type': 'application/json',
                },
                body: JSON.stringify({
                    orderID: data.orderID
                })
            .then(function(res){
                console.log(res);  //// ADD THIS
                if(!res.ok){
                    throw new Error('Bad response from server.php');
                }

                window.location('succes.php');
            });