没有随机音乐文件播放器打开的文件

Question

我发现编写Python音乐播放器的难度比播放随机艺术家要困难。我在目录中有mp3文件，但随机选择它们证明是困难的。任何帮助将不胜感激，谢谢！

from tkinter import *

import os

import random

master = Tk()
var = IntVar()
var.set(1)

def quit_loop():
    print ("Selection:"),var.get()

    global selection
    selection = var.get()
    master.quit()

Label(master, text = "What is your mood?").grid(row=0, sticky=W)

Radiobutton(master, text = "Sad", variable=var, value = 1).grid(row=1,sticky=W)

Radiobutton(master, text = "Happy", variable=var, value = 2).grid(row=2, sticky=W)

Radiobutton(master, text = "Sleepy or Bored", variable=var, value = 3).grid(row=3, sticky=W)

Radiobutton(master, text = "Scared", variable=var, value = 4).grid(row=4, sticky=W)

Radiobutton(master, text = "Pumped or Angry", variable=var, value = 5).grid(row=5, sticky=W)

Button(master, text = "Show me the music!", command=quit_loop).grid(row=7, sticky=W)


master.mainloop()

if selection == 1:
    print ("My Value is equal to one.")

elif selection == 2:
    print ("My value is equal to two.")

elif selection == 3:
    print ("My value is equal to three.")

elif selection == 4:
    print ("My value is equal to four.")

elif selection == 5:
    random.choice(os.listdir(r"C:\Users\Steven\Desktop\Dony Proj\Mood DJ\Do you like any of these\Beastie Boys"))

Answer 1

好吧，你正在调用random.choice，但没有给任何东西分配返回值。

Answer 2

你似乎已经拥有它;我使用一些示例音乐文件将目录设置为我的机器中的一个目录，并将随机选择的文件存储到变量中并添加了一个print语句以查看它是什么：

elif selection == 5:
    song_choice = random.choice(os.listdir(r"E:\music"))
    print(song_choice)

然后它会从我的音乐目录中打印一首随机歌曲的名称！