鉴于以下代码:
using System;
using System.Xml.Schema;
using System.Xml.Serialization;
namespace XmlSerializationTest
{
[XmlType(Namespace = "http://www.test.com")]
public class Element
{
[XmlElement]
public int X;
}
[XmlRoot(Namespace = "http://www.test.com")]
public class Root
{
[XmlElement(Form = XmlSchemaForm.Unqualified)]
public Element Element;
}
public static class Program
{
public static void Main(string[] args)
{
var root = new Root { Element = new Element { X = 1 } };
var xmlSerializer = new XmlSerializer(typeof(Root));
xmlSerializer.Serialize(Console.Out, root);
}
}
}
输出是:
<?xml version="1.0" encoding="ibm852"?>
<Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.test.com">
<Element xmlns="">
<X xmlns="http://www.test.com">1</X>
</Element>
</Root>
问题是为什么将Form属性设置为XmlSchemaForm.Unqualified
会导致Element
元素的命名空间设置为""
,即使它具有与Root元素具有相同名称空间的XmlTypeAttribute
属性?
这种代码(XmlSchemaForm.Unqualified
部分)是由WSCF.blue
工具生成的,它正在弄乱命名空间。
您可以覆盖元素类型中指定的命名空间。例如。你可以有
[XmlElement(Namespace="http://foo.com")]
public Element Element;
输出就是
<Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.test.com">
<Element xmlns="http://foo.com">
<X xmlns="http://www.test.com">1</X>
</Element>
</Root>
微软对Form = XmlSchemaForm.Unqualified
的实现似乎完全等同于将Namespace
设置为""
。特别是,如果您明确指定了任何其他命名空间(MSDN reference),则无法使用它。如果你这样做,你会得到这个例外:
Unhandled Exception: System.InvalidOperationException: There was an error reflecting type 'XmlSerializationTest.Root'. ---> System.InvalidOperationException: There was an error reflecting field 'Element'. ---> System.InvalidOperationException: The Form property may not be 'Unqualified' when an explicit Namespace property is present.