更具体而言,我对集合排序有问题
Output:
[B_Author: Movie_X, A_Author: Movie_A, A_Author: Movie_B]
Should Be:
[A_Author: Movie_A, A_Author: Movie_B, B_Author: Movie_X]
应该这样做的方法(在MovieStorage类中:)>
public Set<Movie> getCatalogue(Comparator<Movie> comp){ List<Movie> sett = new ArrayList<>(this.movieList); sett.sort(comp); return new HashSet<>(sett); }
实现比较器的类:
public class MovieComparator implements Comparator<Movie> { @Override public int compare(Movie a, Movie b) { if (a.getName().compareTo(b.getName()) == 0){ return a.getAuthor().compareTo(b.getAuthor()); } return a.getName().compareTo(b.getName()); } }
称为方法:
System.out.println(movieStorage.getCatalogue(new MovieComparator()));
我一直在寻找StackOverflow和其他网站,但是我注意到每个人都根据1个参数对它进行排序(这对我也不起作用),同时,代码与我的代码几乎相同。 。>
非常感谢您的帮助:)
更具体而言,我对馆藏排序有问题输出:[B_Author:Movie_X,A_Author:Movie_A,A_Author:Movie_B]应该是:[A_Author:Movie_A,A_Author:Movie_B,B_Author:Movie_X ...
创建比较器的更紧凑的方法:
Comparator<Movie> comparator =
Comparator.comparing(Movie::getName).thenComparing(Movie::getAuthor);
Set<Movie> movies = new TreeSet<>(comparator);
movies.addAll(movieList);