从BigDecimal获取减少的分数

Question

我正在执行一些非常精确的十进制计算，最后我将其转换为减少的分数。小数位数需要精确到96个小数位数。

由于精度非常重要，因此我使用BigDecimal和BigInteger。

BigDecimal的计算总是返回正确的十进制值，但在某些情况下，我无法将此十进制转换为小数的函数

假设我有一个BigDecimal d

d.toString() = 32.222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222223

当我的函数试图将其转换为分数时，输出

Decimal from BigDecimal is:  
32.222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222223

// Run the BigDecimal into getFraction
Denominator before reducing:
1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
Numerator before reducing:
32222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222223

// Reduced fraction turns into:
-1/0


// But should output
290/9

这是我的将小数减为小数的功能：

static int[] getFraction(BigDecimal x) {
        BigDecimal x1 = x.stripTrailingZeros();
        //System.out.println(x.toString() + " stripped from zeroes");
        //System.out.println(x1.scale());

        // If scale is 0 or under we got a whole number fraction something/1
        if(x1.scale() <= 0) {
            //System.out.println("Whole number");
            int[] rf = { x.intValue(), 1 };
            return rf;
        }

        // If the decimal is 
        if(x.compareTo(BigDecimal.ZERO) < 0) {
            // Add "-" to fraction when printing from main function
            // Flip boolean to indicate negative decimal number
            negative = true;

            // Flip the BigDecimal
            x = x.negate();
            // Perform same function on flipped
            return getFraction(x);
        }

        // Split BigDecimal into the intval and fractional val as strings
        String[] parts = x.toString().split("\\.");

        // Get starting numerator and denominator
        BigDecimal denominator = BigDecimal.TEN.pow(parts[1].length()); 
        System.out.println("Denominator :" + denominator.toString());

        BigDecimal numerator = (new BigDecimal(parts[0]).multiply(denominator)).add(new BigDecimal(parts[1]));
        System.out.println("Numerator :" + numerator.toString());

        // Now we reduce
        return reduceFraction(numerator.intValue(), denominator.intValue());
    }

    static int[] reduceFraction(int numerator, int denominator) {
        // First find gcd
        int gcd = BigInteger.valueOf(numerator).gcd(BigInteger.valueOf(denominator)).intValue(); 
        //System.out.println(gcd);


        // Then divide numerator and denominator by gcd
        int[] reduced = { numerator / gcd, denominator / gcd };

        // Return the fraction
        return reduced;
    }

如果有人弄清楚我是否犯了任何错误，我将不胜感激！

**更新**

已更改的reduceFraction函数：现在返回String []而不是int []

static String[] reduceFraction(BigDecimal numerator, BigDecimal denominator) {
        // First find gcd
        BigInteger nu = new BigInteger(numerator.toString());
        BigInteger de = new BigInteger(denominator.toString());
        BigInteger gcd = nu.gcd(de);

        // Then divide numerator and denominator by gcd
        nu = nu.divide(gcd);
        de = de.divide(gcd);
        String[] reduced = { nu.toString(), de.toString() };

        // Return the fraction
        return reduced;
    }

getFraction返回：

// Now we reduce, send BigDecimals for numerator and denominator
        return reduceFraction(num, den);

而不是

// Now we reduce
        return reduceFraction(numerator.intValue(), denominator.intValue());

仍然从函数中得到错误的答案

现在的输出分数是

// Gcd value
gcd = 1

// Fraction is then:
32222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222223/1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

//gcd Value should be:
gcd = 111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

// Whit this gcd the fraction reduces to: 
290/9

Answer 1

// Now we reduce
return reduceFraction(numerator.intValue(), denominator.intValue());

嗯，在这种情况下这一定会失败，因为这里的分子或分母都不适合int。

分子变为-1908874353，并且在它们上调用intValue()后分母变为0。您必须携带BigIntegers直到计算结束。

[在将它们转换为int或long之前，如果必须这样做，可以通过将它们与Integer.MIN_VALUE，Integer.MAX_VALUE，Long.MIN_VALUE进行比较来检查是否可以将它们转换为那些类型，而不会损失精度。和Long.MAX_VALUE。