同一列中的不同记录明智重复

Question

我有下面的示例表，其中我在不同时间戳收到了重复的 ID。 我需要计算一天内收到的不同 ID 的数量以及当天收到的重复项的数量

select trunc(date)  ,count(distinct id) ,COUNT(*) AS COUNTS 
from abc
where trunc(date)=trunc(sysdate)
group by trunc(date)
HAVING COUNT(*)>1;

下表是示例数据。

 date        id
1/1/2024    1011
1/1/2024    1012
1/1/2024    1011
1/1/2024    1014
1/2/2024    1014
1/2/2024    1014

我需要得到以下结果。我无法获得当天的重复总数。

date    distinct id  no. of duplicates on that day
1/1/2024    3            2
1/2/2024    1            2

Answer 1

我在 CTE 中完成了这两项计算，然后在日期上为您将它们合并在一起。

WITH CTE
AS (
       SELECT
           [date],
           COUNT(DISTINCT ID) as 'distinct id'
       FROM
           MyTable
       group by
           [date]
   ),
     CTE2
AS (
       SELECT
           date,
           id,
           COUNT(id) as 'no. of duplicates on that day'
       FROM
           MyTable T
       group by
           date,
           id
       HAVING
           COUNT(id) > 1
   )
SELECT
    CTE2.date,
    [distinct id],
    [no. of duplicates on that day]
FROM
    CTE2
    JOIN
        CTE
            ON CTE.date = CTE2.date