是否有一种方法,最好使用LibVLCSharp在C#中转发RTSP,

问题描述 投票:1回答:1

我正在尝试创建可加重多个RTSP的应用程序,以用于移动应用程序。我的想法是,我在连接到IP摄像机的Windows PC上运行一个简单的WPF应用,然后将xamarin应用连接到它。我希望WPF程序可以根据需要将所需的RTSP中继到应用程序,但是这样做我很茫然。我学习了如何在Windows和Android应用程序上接收流,但是我正在寻找一种将Windows应用程序接收到的流转发到Android设备中的方法。

根据我发现的潜伏在互联网上的情况,有一种使用VLC库进行流式传输的方法:How to streaming video via VLC api in C#

但是我不知道如何从另一个流而不是一个文件流。

这就是我所得到的-在应用程序上简单显示RTSP:

        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:Serwer"
        xmlns:wpf="clr-namespace:LibVLCSharp.WPF;assembly=LibVLCSharp.WPF"
        mc:Ignorable="d"
        Title="MainWindow" Height="650" Width="800">
    <Grid>
        <Grid.RowDefinitions>
            <RowDefinition Height="*"/>
            <RowDefinition Height="*"/>
        </Grid.RowDefinitions>
        <Grid.ColumnDefinitions>
            <ColumnDefinition  Width="*"/>
            <ColumnDefinition  Width="*"/>
        </Grid.ColumnDefinitions>
        <Label Grid.Row="0" Grid.Column="0">Placeholder for settings</Label>
        <Label Grid.Row="0" Grid.Column="1">Placeholder for more streams</Label>
        <Label Grid.Row="1" Grid.Column="1"></Label>
        <wpf:VideoView x:Name="VideoView" Grid.Row="1" Grid.Column="0"/>
    </Grid>
</Window>

这是XAML背后的代码:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;

namespace Serwer
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        const string VIDEO_URL = "rtsp://wowzaec2demo.streamlock.net/vod/mp4:BigBuckBunny_115k.mov";
        readonly LibVLC _libvlc;

        public MainWindow()
        {
            InitializeComponent();
            // this will load the native libvlc library (if needed, depending on the platform). 
            Core.Initialize();

            // instantiate the main libvlc object
            _libvlc = new LibVLC();
            VideoView.MediaPlayer = new LibVLCSharp.Shared.MediaPlayer(_libvlc);
            VideoView.MediaPlayer.Play(new Media(_libvlc, VIDEO_URL, FromType.FromLocation));
        }
    }
}
c# stream rtsp libvlcsharp
1个回答
0
投票

好吧,我终于找到了命令列表并正确使用了它们。原来我爱上了LibVLC。 :D这是描述各种命令的链接:https://wiki.videolan.org/Documentation:Streaming_HowTo/Advanced_Streaming_Using_the_Command_Line/#rtp

这是我完成代码的方式:

using LibVLCSharp.Shared;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;

namespace Serwer
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        const string VIDEO_URL = "rtsp://wowzaec2demo.streamlock.net/vod/mp4:BigBuckBunny_115k.mov";
        readonly LibVLC _libvlc;

        public MainWindow()
        {
            InitializeComponent();            // this will load the native libvlc library (if needed, depending on the platform). 
            Core.Initialize();                // instantiate the main libvlc object
            _libvlc = new LibVLC();
            VideoView.MediaPlayer = new LibVLCSharp.Shared.MediaPlayer(_libvlc);
            var rtsp1 = new Media(_libvlc, VIDEO_URL, FromType.FromLocation);       //Create a media object and then set its options to duplicate streams - 1 on display 2 as RTSP
            rtsp1.AddOption(":sout=#duplicate" +
                "{dst=display{noaudio}," +
                "dst=rtp{mux=ts,dst=192.168.0.110,port=8080,sdp=rtsp://192.168.0.110:8080/go.sdp}");  //The address has to be your local network adapters addres not localhost
            VideoView.MediaPlayer.Play(rtsp1);
            VideoView1.MediaPlayer = new LibVLCSharp.Shared.MediaPlayer(_libvlc);
            VideoView1.MediaPlayer.Mute=true;
            VideoView1.MediaPlayer.Play(new Media(_libvlc, "rtsp://192.168.0.110:8080/go.sdp", FromType.FromLocation));
        }
    }
}

感谢立方体指向正确的方向!

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