我有一个很长的字符串,是系统发育树,我想进行非常特定的过滤。
(Esy@ESY15_g64743_DN3_SP7_c0:0.0726396855636,Aar@AA_maker7399_1:0.137507902808,((Spa@Tp2g18720:0.0318934795022,Cpl@CP2_g48793_DN3_SP8_c:0.0273465005242):9.05326020871e-05,(((Bst@Bostr_13083s0053_1:0.0332592496158,((Aly@AL8G21130_t1:0.0328569260951,Ath@AT5G48370_1:0.0391706378372):0.0205924636564,(Chi@CARHR183840_1:0.0954469923893,Cru@Carubv10026342m:0.0570981548016):0.00998579652059):0.0150356382287):0.0340484449097,(((Hco@scaff1034_g23864_DN3_SP8_c_TE35_CDS100:0.00823215335663,Hlo@DN13684_c0_g1_i1_p1:0.0085462978729):0.0144626717872,Hla@DN22821_c0_g1_i1_p1:0.0225079453622):0.0206478928557,Hse@DN23412_c0_g1_i3_p1:0.048590776459):0.0372829371381):0.00859075940423,(Esa@Thhalv10004228m:0.0378509854703,Aal@Aa_G102140_t1:0.0712272454125):1.00000050003e-06):0.00328120860999):0.0129090235079):0.0129090235079;
基本上每个x@y
是一个species@gene_id
信息。我正在尝试将其缩小以使我只有x
而不是x@y
。
(Esy, Aar,(Spa,Cpl))...
我先尝试拆分字符串,但问题是字符串对于我要实现的目标具有不同的'拆分点',即x@y
的某些部分以,
结尾,而另一些部分的)
结尾。我搜索了一个解决方案并看到了正则表达式操作,但是我是Python的新手,我不确定这是否是我应该关注的重点。我也考虑过strip()
,但似乎需要为此指定要删除的字符。
主要问题是我没有告诉Python遵循的'模式'。唯一的事情是所有物种ID均为3个字母,且位于@
字符之前。
是否有可以执行我想要的方法?如果您能帮助我解决我的问题,我将非常高兴。预先感谢。
这种功能怎么样:
def parse_string(string):
new_string = ''
skip = False
for char in string:
if char == '@':
skip = True
if char == ',':
skip = False
if not skip or char in ['(', ')']:
new_string += char
return new_string
在您的字符串上调用:
string = '(Esy@ESY15_g64743_DN3_SP7_c0:0.0726396855636,Aar@AA_maker7399_1:0.137507902808,((Spa@Tp2g18720:0.0318934795022,Cpl@CP2_g48793_DN3_SP8_c:0.0273465005242):9.05326020871e-05,(((Bst@Bostr_13083s0053_1:0.0332592496158,((Aly@AL8G21130_t1:0.0328569260951,Ath@AT5G48370_1:0.0391706378372):0.0205924636564,(Chi@CARHR183840_1:0.0954469923893,Cru@Carubv10026342m:0.0570981548016):0.00998579652059):0.0150356382287):0.0340484449097,(((Hco@scaff1034_g23864_DN3_SP8_c_TE35_CDS100:0.00823215335663,Hlo@DN13684_c0_g1_i1_p1:0.0085462978729):0.0144626717872,Hla@DN22821_c0_g1_i1_p1:0.0225079453622):0.0206478928557,Hse@DN23412_c0_g1_i3_p1:0.048590776459):0.0372829371381):0.00859075940423,(Esa@Thhalv10004228m:0.0378509854703,Aal@Aa_G102140_t1:0.0712272454125):1.00000050003e-06):0.00328120860999):0.0129090235079):0.0129090235079;'
parse_string(string)
> '(Esy,Aar,((Spa,Cpl),(((Bst,((Aly,Ath),(Chi,Cru))),(((Hco,Hlo),Hla),Hse)),(Esa,Aal))))'
尝试一下:
import re:
pat = re.compile(r'(\w{3})@')
txt = "(Esy@ESY15_g64743_DN3_SP7_c0:0.0726396855636,Aar@AA_maker7399_1:0.137507902808,((Spa@Tp2g18720:0.0318934795022,Cpl@CP2_g48793_DN3_SP8_c:0.0273465005242):9.05326020871e-05,(((Bst@Bostr_13083s0053_1:0.0332592496158,((Aly@AL8G21130_t1:0.0328569260951,Ath@AT5G48370_1:0.0391706378372):0.0205924636564,(Chi@CARHR183840_1:0.0954469923893,Cru@Carubv10026342m:0.0570981548016):0.00998579652059):0.0150356382287):0.0340484449097,(((Hco@scaff1034_g23864_DN3_SP8_c_TE35_CDS100:0.00823215335663,Hlo@DN13684_c0_g1_i1_p1:0.0085462978729):0.0144626717872,Hla@DN22821_c0_g1_i1_p1:0.0225079453622):0.0206478928557,Hse@DN23412_c0_g1_i3_p1:0.048590776459):0.0372829371381):0.00859075940423,(Esa@Thhalv10004228m:0.0378509854703,Aal@Aa_G102140_t1:0.0712272454125):1.00000050003e-06):0.00328120860999):0.0129090235079):0.0129090235079;"
pat.findall(t)
结果:
['Esy', 'Aar', 'Spa', 'Cpl', 'Bst', 'Aly', 'Ath', 'Chi', 'Cru', 'Hco', 'Hlo', 'Hla', 'Hse', 'Esa', 'Aal']