SQL Server表关系

问题描述 投票:4回答:4

SQL Server Mgmt Studio 2005:有人可以帮助我了解如何查看和打印表之间的关系,同时显示表中的列。我很多年前就这样做了,并且已经挣扎了好几天再做一次。

sql sql-server-2005 relational-database
4个回答
7
投票

右键单击数据库名称,展开“Database Diagrams”并选择:“New Database Diagram”。


3
投票

您需要创建和编辑数据库图表,请参阅此Getting started with SQL Server database diagrams和/或Designing Database Diagrams

您也可以使用查询来执行此操作:SQL SERVER – Query to Display Foreign Key Relationships and Name of the Constraint for Each Table in Database

这是一个查询,它将从@TableName获取PKs,Check Constraints和FKs,并在逗号分隔列表中使用多列约束:

DECLARE @TableName varchar(250)
SET @TableName='YourTable'
;WITH AllInfo AS
(
SELECT
    tc.TABLE_NAME,tc.CONSTRAINT_NAME, ccu.COLUMN_NAME
    FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS                  tc
        INNER JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE  ccu ON ccu.TABLE_NAME = tc.TABLE_NAME AND ccu.CONSTRAINT_NAME = tc.CONSTRAINT_NAME
    WHERE tc.TABLE_NAME =@TableName
UNION
SELECT
    FK.TABLE_NAME,C.CONSTRAINT_NAME,CU.COLUMN_NAME
    FROM INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS      C
        INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS FK ON C.CONSTRAINT_NAME = FK.CONSTRAINT_NAME
        INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS PK ON C.UNIQUE_CONSTRAINT_NAME = PK.CONSTRAINT_NAME
        INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE  CU ON C.CONSTRAINT_NAME = CU.CONSTRAINT_NAME
        INNER JOIN (SELECT i1.TABLE_NAME, i2.COLUMN_NAME
                        FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS          i1
                            INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE i2 ON i1.CONSTRAINT_NAME = i2.CONSTRAINT_NAME
                            WHERE i1.CONSTRAINT_TYPE = 'PRIMARY KEY'
                   ) PT ON PT.TABLE_NAME = PK.TABLE_NAME
        WHERE PK.TABLE_NAME=@TableName
)
SELECT DISTINCT
    t1.TABLE_NAME,t1.CONSTRAINT_NAME
        ,STUFF(
                   (SELECT
                        ', ' + t2.COLUMN_NAME
                        FROM AllInfo t2
                        WHERE t1.TABLE_NAME=t2.TABLE_NAME AND t1.CONSTRAINT_NAME=t2.CONSTRAINT_NAME
                        ORDER BY t2.COLUMN_NAME
                        FOR XML PATH(''), TYPE
                   ).value('.','varchar(max)')
                   ,1,2, ''
              ) AS ColumnNames
    FROM AllInfo t1
    ORDER BY 1,2,3

0
投票

您可以创建数据库图表并将所有表格添加到其中。如果这是您想要的,它将是一个图形表示。


0
投票

您可以使用以下脚本来查找特定表的所有fk,pk关系

DECLARE @tablename VARCHAR(100)
SET @tablename='xxxxxxx'
Select 'Referenced by FK table' AS Type,  FK.TABLE_SCHEMA, FK.TABLE_NAME AS 'FK_TABLE_NAME' ,cu.COLUMN_NAME AS 'FK_ReferencingColumn',PK.TABLE_NAME AS 'PK_TABLE_NAME',
 ku.COLUMN_NAME AS 'PK_ReferencedColumn'
From INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS As RC
    Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As PK
        On PK.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME
    Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As FK
        On FK.CONSTRAINT_NAME = RC.CONSTRAINT_NAME
   JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE cu
   ON cu.CONSTRAINT_NAME = Rc.CONSTRAINT_NAME
     JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE ku
ON ku.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME
Where 
    PK.TABLE_NAME = @tablename
UNION  
SELECT 'Referencing PK table' AS Type, FK.TABLE_SCHEMA, FK.TABLE_NAME AS 'FK_TABLE_NAME' ,cu.COLUMN_NAME AS 'FK_ReferencingColumn',PK.TABLE_NAME AS 'PK_TABLE_NAME',
 ku.COLUMN_NAME AS 'PK_ReferencedColumn'
From INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS As RC
    Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As PK
        On PK.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME
    Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As FK
        On FK.CONSTRAINT_NAME = RC.CONSTRAINT_NAME
   JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE cu
   ON cu.CONSTRAINT_NAME = Rc.CONSTRAINT_NAME
     JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE ku
ON ku.CONSTRAINT_NAME = RC.UNIQUE_CONSTRAINT_NAME
Where 
     fk.TABLE_NAME = @tablename
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