EditText在选择时失去背景

问题描述 投票:0回答:1

我有一个EditText盒子有自定义drawable背景,但每当你选择EditText输入的东西背景消失,使文本无法读取(它是与应用程序背景相同的颜色)

这就是我所说的:

enter image description here

enter image description here

背景刚刚消失,我不知道为什么会这样。这是我的.xml

    <EditText
    android:id="@+id/enterCode"
    android:layout_width="237sp"
    android:layout_height="55sp"
    android:layout_marginStart="8dp"
    android:layout_marginTop="8dp"
    android:layout_marginEnd="6dp"
    android:layout_marginBottom="8dp"
    android:autofillHints="true"
    android:background="@drawable/rect_yellow_border"
    android:ems="10"
    android:hint="Enter Game PIN"
    android:inputType="text"
    android:textAlignment="center"
    android:textColor="@color/colorPrimary"
    android:textColorHint="#40292929"
    app:layout_constraintBottom_toBottomOf="parent"
    app:layout_constraintEnd_toEndOf="parent"
    app:layout_constraintHorizontal_bias="0.503"
    app:layout_constraintStart_toStartOf="parent"
    app:layout_constraintTop_toBottomOf="@+id/products_toolbar"
    app:layout_constraintVertical_bias="0.309" />

我也尝试在Java中设置背景但是当我尝试这样做时问题并没有解决。有帮助吗?

这是我的drawable文件。这有点不必要和奇怪,因为我只是编辑了我的一个圆形形状的代码并使其成为一个正方形

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android" >
    <item android:state_pressed="true" >
            <shape android:shape="rectangle"  >
            <stroke android:width="3dip" android:color="#ffc847" />
            <gradient android:angle="-180" android:startColor="#ffffff" android:endColor="#ffffff"  />
        </shape>
    </item>
    <item android:state_focused="true">
        <shape android:shape="rectangle"  >
        </shape>
    </item>
    <item >
        <shape android:shape="rectangle"  >
            <stroke android:width="3dip" android:color="#ffc847" />
            <stroke android:width="3dip" android:color="#ffc847" />
            <solid android:color="#ffc847"/>
            <gradient android:angle="-45" android:startColor="#ffffff" android:endColor="#ffffff" />
        </shape>
    </item>


</selector>

在我的Activity中我所做的一切都是为了定义这个EditText是这样的:

    @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_private_room_lobby);
    final Button createPrivateGame = findViewById(R.id.createPrivateGame);
    final Button joinPrivateRoom = findViewById(R.id.joinPrivateGame);
    final EditText pinEntry = findViewById(R.id.enterCode);

    joinPrivateRoom.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            String pin = pinEntry.getText().toString().trim();
            if(TextUtils.isEmpty(pin) || pin.length() > 6 || pin.length() < 6)
            {
                Toast.makeText(PrivateRoomLobby.this, "Please enter a 6 digit PIN to enter the room", Toast.LENGTH_LONG).show();
            } else {
                joinGame(pin);
            }
        }
    });
xml android-edittext android-drawable
1个回答
1
投票

选择器用于通过各种状态定义view组件的背景颜色或背景图像。有关详细信息,请查看this

你需要使用唯一的shape

    <?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" >



    <stroke android:width="3dip" android:color="#ffc847" />

    <solid android:color="#ffffff"/>
  <!--  <gradient android:angle="-45" android:startColor="#ffffff" android:endColor="#ffffff" />-->

</shape>
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