在一个信号的条件下发送推送通知

Question

如何根据条件为用户创建个性化的推送通知。我已经使用One Signal实现了推送通知，可以在其中向所有用户发送有关股票市场的通知。我想通过实现图片中的类似内容来进一步迈出这一步

在这种情况下，用户可以输入价格，如果价格超过或低于用户给定的价格，则发送推送通知。

Answer 1

我认为在这种情况下，您应该使用Server RestApi创建通知。确定价格后发出请求：

using System.IO;
using System.Net;
using System.Text;

var request = WebRequest.Create("https://onesignal.com/api/v1/notifications") as HttpWebRequest;

request.KeepAlive = true;
request.Method = "POST";
request.ContentType = "application/json; charset=utf-8";

byte[] byteArray = Encoding.UTF8.GetBytes("{"
                                    + "\"app_id\": \"5eb5a37e-b458-11e3-ac11-000c2940e62c\","
                                    + "\"contents\": {\"en\": \"English Message\"},"
                                    + "\"include_player_ids\": [\"6392d91a-b206-4b7b-a620-cd68e32c3a76\",\"76ece62b-bcfe-468c-8a78-839aeaa8c5fa\",\"8e0f21fa-9a5a-4ae7-a9a6-ca1f24294b86\"]}");

string responseContent = null;

try {
   using (var writer = request.GetRequestStream()) {
    writer.Write(byteArray, 0, byteArray.Length);
    }

using (var response = request.GetResponse() as HttpWebResponse) {
    using (var reader = new StreamReader(response.GetResponseStream())) {
        responseContent = reader.ReadToEnd();
    }
  }
}
catch (WebException ex) {
System.Diagnostics.Debug.WriteLine(ex.Message);
System.Diagnostics.Debug.WriteLine(new StreamReader(ex.Response.GetResponseStream()).ReadToEnd());
}

System.Diagnostics.Debug.WriteLine(responseContent);

有关更多信息，请查看onesigna官方文档，google OneSigna> 文档> 服务器REST API> 创建通知