因此,我需要在char字符串中的空格后插入空格:
我们有字符串:hello world
,函数应该返回hello world
hello world something else
=> hello world something else
[hello world
=> hello world
(4个空格)(不一定,但最好)]
如何? (肯定需要使用char字符串)
我的解决方案(由于只能插入1个空格,因此无法正常工作)
从hello world something
返回hello world something
:
#include <iostream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
char* addSpaces(char* str) {
char* p = strchr(str, ' ');
if (p) {
p++;
int n = strlen(p);
p[n + 1] = 0;
while (n) {
p[n] = p[n - 1];
n--;
}
*p = ' ';
}
return str;
}
int main(void) {
const int stringCount = 1;
const int c = 500;
char cstring[stringCount][c];
string str[stringCount];
for (int i = 0; i < stringCount; i++) {
cout << "Enter " << i + 1 << ". line: ";
cin.getline(cstring[i], c);
str[i] = cstring[i];
}
for (int i = 0; i < stringCount; i++) {
cout << "First function result with char in parameter: ";
char* result = addSpaces(cstring[i]);
cout << result << endl;
}
}
首先检查空格,并以len + space开头。并在每次迭代中添加额外的空间。其他错误可能会超出索引范围。
#include <iostream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
int main(void)
{
std::string line;
const int stringCount = 1;
const int c = 500;
cout << "Enter line: ";
std::getline(std::cin, line);
cout << line << endl;
int spaceCount = 0;
for (int i = 0; i < sizeof(line); i++)
{
if (line[i] == ' ')
{
spaceCount += 1;
}
}
char cstring[stringCount + spaceCount];
int j = 0;
for (int i = 0; i < sizeof(line); i++)
{
if (line[i] == ' ')
{
cstring[j++] = ' ';
cstring[j++] = ' ';
}
else
{
cstring[j++] = line[i];
}
}
cout << cstring << endl;
}