Windows上的Python 3.6 subprocess.run（）中的7z命令

Question

我有一个python脚本，应使用命令“ x”运行7z.exe，并使用subprocess.run（）切换“ -o”。脚本如下：

import subprocess as sb


zipperpath = "C:\\Program Files\\7-zip\\7z.exe"
dirname ="C:\\Users\\ajain\\Desktop\\TempData"
archivename="UnprocessedData_v3.7z"
outputfilename="foo"

sb.run([zipperpath,"x",os.path.join(dirname,archivename)," -o",os.path.join(dirname,outputfilename)])

输出为：尽管返回码为0，但邮政编码永远不会解压缩。

Answer 1

尝试一下：

import subprocess

# variable cmd is is your command line , like you put in your console 
cmd='7z.exe x UnprocessedData_v3.7z'

process = subprocess.Popen(cmd,shell=True,stdin=None,stdout=subprocess.PIPE,stderr=subprocess.PIPE)
# The output from your shell command in an array
result=process.stdout.readlines()
if len(result) >= 1:
    for line in result:
        print(line)