尝试与用户的PIN(智能卡)建立会话时出错

问题描述 投票:1回答:1

我正在使用python-pkcs11访问我拥有的智能卡。现在,我正在尝试创建一个会话,以便我可以从卡中检索公钥。这是我测试的代码:

path = (...)
os.environ["PKCS11 MODULE"] = path
lib = pkcs11.lib(os.environ['PKCS11 MODULE'])

password = bytes("1234","utf-8")
print(password)

with token.open(user_pin=password) as session:
    print(session) 

一切看起来都不错,直到达到“user_pin = password”。我收到一个错误:

Traceback (most recent call last):
    File "acess.py", line 46, in <module>
    with token.open(user_pin=password) as session:
    File "pkcs11/_pkcs11.pyx", line 227, in pkcs11._pkcs11.Token.open
    AttributeError: 'bytes' object has no attribute 'encode'

在文档中,据说user_password必须以字节为单位,这就是我正在做的事情。有人能帮助我吗?

编辑:

当我测试这3种情况中的任何一种时,我仍然会收到错误:

with token.open(user_pin='1234') as session:
    print(session)

with token.open(user_pin=b"1234") as session:
    print(session)

with token.open(user_pin="1234") as session:
    print(session)

错误:

Traceback (most recent call last):
      File "acess.py", line 59, in <module>
        with token.open(user_pin="1234") as session:
      File "pkcs11/_pkcs11.pyx", line 239, in pkcs11._pkcs11.Token.open
      File "pkcs11/_errors.pyx", line 88, in pkcs11._pkcs11.assertRV
        pkcs11.exceptions.UserPinNotInitialized
python security cryptography smartcard pkcs#11
1个回答
0
投票

你错过了这一行:

token = lib.get_token(token_label ='your token Label')

使用token.open(user_pin =“1234”)作为session:print(session

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