获取Google地图中搜索区域中所有标记的列表 - Markerclusterer v3 [复制]

Question

这个问题在这里已有答案：

• How to get all visible markers on current zoom level 5个答案

我需要在Google地图的缩放区域中获取标记列表。

我查看了另一个问题：Get a list of markers in bounds of google map using markerclusterer v3

哪个接近我想要的，但不完全一样。

这是我生成地图的JavaScript

$('#autocomplete').click(function() {
  $(this).val('');
   $(this).attr('placeholder', '');
});
var map, places, infoWindow;
var markers = [];
var autocomplete;
var countryRestrict = {
    'country': 'dk'
};

function initMap() {

    map = new google.maps.Map(document.getElementById('map'), {
        zoom: 7,
        center: {
            lat: 56.220512,
            lng: 11.245051
        },
        mapTypeControl: false,
        panControl: true,
        zoomControl: true,
        streetViewControl: false
    });

    autocomplete = new google.maps.places.Autocomplete(
        (
            document.getElementById('autocomplete')), {
            componentRestrictions: countryRestrict
        });
    places = new google.maps.places.PlacesService(map);

    autocomplete.addListener('place_changed', onPlaceChanged);

    setMarkers(map);
    var marker = new google.maps.Marker({
        map: map,
        anchorPoint: new google.maps.Point(0, -29)
    });

    autocomplete.addListener('place_changed', function() {
        marker.setVisible(false);
        var place = autocomplete.getPlace();
        if (!place.geometry) {
            event.preventDefault();
        }

        if (place.geometry.viewport) {} else {
            map.setCenter(place.geometry.location);
            map.setZoom(10);
        }
        marker.setPosition(place.geometry.location);
        marker.setVisible(true);

        var address = '';
        if (place.address_components) {
            address = [
                (place.address_components[0] && place.address_components[0].short_name || ''),
                (place.address_components[1] && place.address_components[1].short_name || ''),
                (place.address_components[2] && place.address_components[2].short_name || '')
            ].join(' ');
        }

    });
}
var beaches = [
    <?php while ( have_rows('tilfoj_vaerksted_repeater') ) : the_row(); ?>

    ['test', <?php the_sub_field('latitude_tilfoj_vaerksted_repeater'); ?>, <?php the_sub_field('longitude_tilfoj_vaerksted_repeater'); ?>, 4],
    <?php endwhile; ?>

];

function setMarkers(map) {
    for (var i = 0; i < beaches.length; i++) {
        var beach = beaches[i];
        var marker = new google.maps.Marker({
            position: {
                lat: beach[1],
                lng: beach[2]
            },
            map: map,
            icon: "/wp-content/uploads/2019/03/map-icon.png",
        });
    }
}

function onPlaceChanged() {

    var place = autocomplete.getPlace();
    if (place.geometry) {
        map.panTo(place.geometry.location);
        map.setZoom(10);
    } else {
        document.getElementById('autocomplete').placeholder = 'Søg';
    }


}

我真正需要的是在Google地图中的搜索区域中获取所有标记，然后隐藏/显示Google地图下方的div元素。您可以在下面的链接中看到当前示例。我想我可以使用Markercluster，但我不太清楚如何做到这一点。

这是生产站点的链接：

Answer 1

我找到了一个完美的解决方案。

function showVisibleMarkers() {
var bounds = map.getBounds(),
    count = 0;

for (var i = 0; i < markers.length; i++) {
    var marker = markers[i], // array indexes start at zero, but not our class names :)
        infoPanel = jQuery('.workplace' + (i)); // array indexes start at zero, but not our class names :)
    if (bounds.contains(marker.getPosition()) === true) {
        infoPanel.show();
        count++;
    } else {
        infoPanel.hide();
    }
}

}

function setMarkers(map) {

for (var i = 0; i < beaches.length; i++) {
    var beach = beaches[i],
        myLatLng = new google.maps.LatLng(beach[1], beach[2]),
        marker = new google.maps.Marker({
            position: myLatLng,
            title: beach[0],
            icon: "/wp-content/uploads/2019/03/map-icon.png",
        });
    marker.setMap(map);

    markers.push(marker);
}

}