当我检索Bundle参数时,为什么会出现空指针异常?

问题描述 投票:-1回答:1

我正在尝试在MyActivity中创建一个片段,传递它需要显示的数据。我正在尝试通过静态方法newInstance()将所有数据打包在一个包中

然而,当我打开活动时,当我尝试在onCreateView()中解压缩包时,我得到一个Null Pointer Exception

Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'int android.os.Bundle.getInt(java.lang.String, int)' on a null object reference

这发生在第一次调用getInt()时,这让我相信getArguments()由于某种原因正在返回一个空包,我无法理解为什么会这样。

my activity.Java

/* Create Status Bar fragment */
FragmentManager fragMngr = getSupportFragmentManager();
frag = (StatusBarFragment)fragMngr.findFragmentById(R.id.f_container2);
if (frag == null)
{
    frag = StatusBarFragment.newInstance(player.getMoney(),
                                         player.getHealth(),
                                         player.getEquipmentMass());
    fragMngr.beginTransaction().add(R.id.f_container2, frag).commit();
 }

status bar fragment.Java

public class StatusBarFragment extends Fragment
{
    private static final String MONEY = "vg.my.citruscode.money";
    private static final String HEALTH = "vg.my.citruscode.health";
    private static final String EQUIPMENT_MASS = "vg.my.citruscode.equipmentMass";

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState)
    {
        View parentView = inflater.inflate(R.layout.fragment_status_bar, container, false);
        Bundle args = getArguments();

        // Omitted methods which update UI Elements
        updateMoney(args.getInt(MONEY, 0)); // This line causes exception
        updateHealth(args.getDouble(HEALTH, 0.0));
        updateEquipmentMass(args.getDouble(EQUIPMENT_MASS, 0.0));

        return parentView;
    }

    public static StatusBarFragment newInstance(int money, double health, double equipmentMass)
    {
        StatusBarFragment frag = new StatusBarFragment();
        Bundle args = new Bundle();

        args.putInt(MONEY, money);
        args.putDouble(HEALTH, health);
        args.putDouble(EQUIPMENT_MASS, equipmentMass);

        frag.setArguments(args);
        return frag;
    }
}
java android android-fragments
1个回答
-2
投票

奇怪的方法。我认为args与数据之间缺少联系。在newInstance()上执行此操作.MONEY = money和其他字符串。

© www.soinside.com 2019 - 2024. All rights reserved.