我想用我的应用程序录制M4A格式的音频文件,然后播放。我的应用程序在我第一次尝试录制时没有这样做,但是在第二次,第三次及以后的尝试中都无法正常工作。打印audioPlayer.duration的值表明,第一个音频记录始终为负值!为什么??如预期的那样,所有其他音频记录的正持续时间值都以秒为单位。我总是对所有记录使用相同的文件名,覆盖以前的记录。我在做什么错?
func initializeRecorder(){
let recordSettings = [AVSampleRateKey : NSNumber(float: Float(32000.0)),
AVFormatIDKey : NSNumber(int: Int32(kAudioFormatMPEG4AAC)),
AVNumberOfChannelsKey : NSNumber(int: 1),
AVEncoderAudioQualityKey : NSNumber(int: Int32(AVAudioQuality.Low.rawValue)) ]
var error : NSError?
let audioSession = AVAudioSession.sharedInstance()
do {
try audioSession.setCategory(AVAudioSessionCategoryPlayAndRecord)
try audioRecorder = AVAudioRecorder(URL: self.directoryURL(),
settings: recordSettings)
audioRecorder.delegate = self
audioRecorder.meteringEnabled = true
audioRecorder.prepareToRecord()
print("M4a Recorder Initialized - OK...")
} catch {
print("Init Error")
}
}
func recordSpeechM4A(){
if !audioRecorder.recording {
isCapioRecording=true
let audioSession = AVAudioSession.sharedInstance()
do {
try audioSession.setActive(true)
print("**** RECORDING ****")
audioRecorder.record()
} catch {
print("RECORDING ERROR")
}
}
}
func stopRecording(){
audioRecorder.stop()
}
func playRecordedAudio(){
if (!audioRecorder.recording){
do {
try audioPlayer = AVAudioPlayer(contentsOfURL: audioRecorder.url)
audioPlayer.play()
print("PLAYING AUDIO...: "+audioRecorder.url.description)
print("Audio duration: "+audioPlayer.duration.description)
//DURATION OF THE 1st RECORDING IS ALWAYS NEGATIVE!!!
} catch {
print("AUDIO PLAYBACK ERROR")
}
}
}
// I ALWAYS USE THE SAME FILENAME!
func directoryURL() -> NSURL {
let fileManager = NSFileManager.defaultManager()
let urls = fileManager.URLsForDirectory(.DocumentDirectory, inDomains: .UserDomainMask)
filepath = urls[0]
let documentDirectory = urls[0] as NSURL
print("STORAGE DIR: "+documentDirectory.description)
let soundURL = documentDirectory.URLByAppendingPathComponent("sound.m4a") //.m4a
print("SAVING FILE: "+soundURL.description)
return soundURL
}
我有一个类似的问题,并通过以下代码段进行了修复:
audioRecorder.record()
audioRecorder.record()
通过两次调用此函数,尽管这可能不是理想的解决方案。它以某种方式解决了它。