Android JAVA RX例外仅来自Play商店

问题描述 投票:1回答:1

大家好,我在谷歌播放控制台的RX上有这个例外,我从来没有在我的项目中看到它,但它发生了大约200次谷歌播放说...任何人对此有所了解?

java.lang.IllegalStateException:

 at rx.android.schedulers.LooperScheduler$ScheduledAction.run (LooperScheduler.java:114)

  at android.os.Handler.handleCallback (Handler.java:739)

  at android.os.Handler.dispatchMessage (Handler.java:95)

  at android.os.Looper.loop (Looper.java:158)

  at android.app.ActivityThread.main (ActivityThread.java:7230)

  at java.lang.reflect.Method.invoke (Native Method)

  at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run (ZygoteInit.java:1230)

  at com.android.internal.os.ZygoteInit.main (ZygoteInit.java:1120)

**Caused by: rx.exceptions.OnErrorFailedException:** 

  at rx.observers.SafeSubscriber._onError (SafeSubscriber.java:187)

  at rx.observers.SafeSubscriber.onError (SafeSubscriber.java:115)

  at rx.exceptions.Exceptions.throwOrReport (Exceptions.java:216)

  at rx.observers.SafeSubscriber.onNext (SafeSubscriber.java:139)

  at rx.internal.operators.OnSubscribeDoOnEach$DoOnEachSubscriber.onNext (OnSubscribeDoOnEach.java:101)

  at rx.internal.operators.OperatorObserveOn$ObserveOnSubscriber.call (OperatorObserveOn.java:224)

  at rx.android.schedulers.LooperScheduler$ScheduledAction.run (LooperScheduler.java:107)
java android system.reactive
1个回答
0
投票

您的代码抛出了未捕获的异常。

你有没有为onError指定一个函数?

   [Your Observable].subscribe(value -> {
        // Your onNext code
    }, throwable -> {
        // Handle error
    });
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