批量查找重复内容，谁能帮帮我？

Question

我正在尝试查找重复的 .txt 文件内容。在这种情况下，.txt 文件中的数字。 例如，

1.txt

有以下数字：

1, 2, 3

，

2.txt

有

4, 5, 6

，

3.txt

有

1, 2, 3

，

4.txt

有

7, 8, 9

程序应该指出

1.txt

与

3.txt

相同。

这就是我现在所拥有的，但是有一个问题。 例如，该文件指出相同的文件

1.txt

和

1.txt

，而不是

1.txt

和

3.txt

，有什么办法可以解决这个问题吗？

setlocal enabledelayedexpansion

set "output_file=duplicates.txt"

echo Process started!
echo Please be patient, this may take some moments.

rem Delete the output file if it already exists
if exist "%output_file%" del "%output_file%"

rem Get a list of all .txt files in the current directory
for %%F in (*.txt) do (

    rem Check if the file has already been processed
    if not defined file[%%~nF] (

        rem Read the content of the file into a variable
        set "content="
        for /f "usebackq delims=" %%L in ("%%F") do set "content=!content!%%L"

        rem Compare the content with other .txt files
        for %%G in (*.txt) do (

            rem Check if the file is different, not already processed, and not self-comparison
            if /i not "%%~nxF"=="%%~nF" if not defined file[%%~nxF] (

                rem Read the content of the other file into a variable
                set "other_content="
                for /f "usebackq delims=" %%M in ("%%G") do set "other_content=!other_content!%%M"

                rem Compare the content of the two files
                if "!content!"=="!other_content!" (
                    echo "%%F" = "%%G" >> "%output_file%"
                    set "file[%%~nF]=true"
                    set "file[%%~nxF]=true"
                )
            )
        )
    )
)

rem Display the results
cls
echo Finished!
echo Here are your results:
type "%output_file%"

pause
endlocal