如何在rxSwift和Moya中绑定viewModel中的数据?

问题描述 投票:1回答:1

我正在尝试创建一个应用来从API获取一些新闻,并且我正在使用Moya,RxSwift和MVVM。这是我的ViewModel:

import Foundation
import RxSwift
import RxCocoa

public enum NewsListError {
    case internetError(String)
    case serverMessage(String)
}

enum ViewModelState {
    case success
    case failure
}

protocol NewsListViewModelInput {
    func viewDidLoad()
    func didLoadNextPage()
}

protocol MoviesListViewModelOutput {
    var newsList: PublishSubject<NewsList> { get }
    var error: PublishSubject<String> { get }
    var loading: PublishSubject<Bool> { get }
    var isEmpty: PublishSubject<Bool> { get }
}

protocol NewsListViewModel: NewsListViewModelInput, MoviesListViewModelOutput {}

class DefaultNewsListViewModel: NewsListViewModel{

    func viewDidLoad() {

    }

    func didLoadNextPage() {

    }


    private(set) var currentPage: Int = 0
    private var totalPageCount: Int = 1

    var hasMorePages: Bool {
        return currentPage < totalPageCount
    }
    var nextPage: Int {
        guard hasMorePages else { return currentPage }
        return currentPage + 1
    }

    private var newsLoadTask: Cancellable? { willSet { newsLoadTask?.cancel() } }

    private let disposable = DisposeBag()

    // MARK: - OUTPUT
    let newsList: PublishSubject<NewsList> = PublishSubject()
    let error: PublishSubject<String> = PublishSubject()
    let loading: PublishSubject<Bool> = PublishSubject()
    let isEmpty: PublishSubject<Bool> = PublishSubject()

    func getNewsList() -> Void{
        print("sono dentro il viewModel!")
        NewsDataService.shared.getNewsList()
            .subscribe { event in
                switch event {
                case .next(let progressResponse):
                    if progressResponse.response != nil {
                        do{
                            let json = try progressResponse.response?.map(NewsList.self)
                            print(json!)
                            self.newsList.onNext(json!)
                        }
                        catch _ {
                            print("error try")
                        }
                    } else {
                        print("Progress: \(progressResponse.progress)")
                    }
                case .error( _): break
                // handle the error
                default:
                    break
                }
        }
    }

}

这是我的ViewController,当我尝试绑定到tableNews时,xCode给我以下错误:

Expression type 'Reactive<_>' is ambiguous without more context
import UIKit
import RxSwift
import RxCocoa

class ViewController: UIViewController {

    @IBOutlet weak var tableNews: UITableView!

    let viewModel = DefaultNewsListViewModel()

    var disposeBag = DisposeBag()

    override func viewDidLoad() {
        super.viewDidLoad()

    }

    private func setupBindings() {

        viewModel.newsList.bind(to: tableNews.rx.items(cellIdentifier: "Cell")) {
            (index, repository: NewsList, cell) in
            cell.textLabel?.text = repository.name
            cell.detailTextLabel?.text = repository.url
        }
        .disposed(by: disposeBag)
    }
}

这是从API获取数据的服务:


import Moya
import RxSwift
struct NewsDataService {
    static let shared = NewsDataService()

    private let disposable = DisposeBag()

    private init() {}

    fileprivate let newsListProvider = MoyaProvider<NewsService>()

    func getNewsList() -> Observable<ProgressResponse> {
        self.newsListProvider.rx.requestWithProgress(.readNewsList)
        }
    }

我是rxSwift的新手,我关注了一些文档,但我想知道我是否正在以正确的方式进行工作。我想知道的另一点是如何正确地将tableView绑定到viewModel。感谢您的支持。

ios swift rx-swift rx-cocoa moya
1个回答
0
投票

如评论中的@FabioFelici所述,UITableView.rx.items(cellIdentifier:)期望绑定到包含对象数组的Observable,但您的NewsListViewModel.newsListObservable<NewsList>

这意味着您必须通过地图将数组从NewsList中提取出来(假设它有一个)。如newsList.map { $0.items }.bind(to: ...

此外,您的MoviesListViewModelOutput不应充满主题,而应包含可观察对象。而且我不会理会这些协议,strut很好。

此外,您的视图模型仍然非常必要,并不是真正的Rx样式。构造良好的Rx视图模型不包含重复调用的函数。它只有一个构造函数(或者本身只是一个函数。)创建它,绑定到它,然后就完成了。

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