我想获得所有三个表明细的lvdays总和大于30的员工假。无法为此找到解决方法。
员工:
empcode| MNGR_CODE| MNGR_CODE2
-------|----------|-----------
AA | bb | cc
FF | bb | cc
lvtype:
typeid| desc
------|---------
1 | casual
离开:
leaveid| empcode| lvdays| typeid| Flag| date | reason
-------|--------|-------|-------|-----|-----------|---------
1 | AA | 2 | 1 | 1 | 11-02-2020| NULL
2 | AA | 3 | 1 | 1 | 02-11-2019| NULL
3 | FF | 4 | 1 | 1 | 23-12-2019| NULL
这是我要建立但无法实现目标的查询。
SELECT MNGR_CODE,
MNGR_CODE2,
lt.desc,
l.reason,
l.leaveID
FROM Leave l
INNER JOIN lvtype lt ON l.typeid = lt.typeid
LEFT OUTER HASH JOIN employee em ON em.Emp_Code = l.empcode
WHERE empcode IN ('AA', 'FF')
AND leaveID IN (SELECT leaveID
FROM Leave l
INNER JOIN lvtype lt ON l.typeid = lt.typeid
WHERE l.empcode IN ('AA', 'FF')
GROUP BY l.empcode
HAVING SUM(lvdays) > 30);
如果我正确地关注了您,则可以使用窗口功能:
select *
from (
select
e.mngr_code,
e.mngr_code2,
lt.desc,
l.reason,
l.leaveid,
sum(l.lvdays) over(partition by e.empcode) sum_lvdays
from leave l
inner join lvtype lt on l.typeid = lt.typeid
inner join employee em on em.emp_code = l.empcode
) t
where sum_lvdays > 30
子查询基于您现有的查询,并添加了一个附加列,该列对每个员工的所有叶子进行了窗口求和。外部查询使用窗口总和的结果作为过滤器。
我不确定您在子查询中确实需要left join
,所以我将其更改为inner join
。