获取Sql-Server中逗号分隔值中未分组列的详细信息

问题描述 投票:0回答:1

我想获得所有三个表明细的lvdays总和大于30的员工假。无法为此找到解决方法。

员工:

empcode| MNGR_CODE| MNGR_CODE2
-------|----------|-----------
AA     |   bb     |     cc 
FF     |   bb     |     cc

lvtype:

typeid| desc
------|---------
1     | casual

离开:

leaveid| empcode| lvdays| typeid| Flag| date      | reason 
-------|--------|-------|-------|-----|-----------|---------
1      |  AA    | 2     |    1  |  1  | 11-02-2020| NULL 
2      |  AA    | 3     |    1  |  1  | 02-11-2019| NULL
3      |  FF    | 4     |    1  |  1  | 23-12-2019| NULL

这是我要建立但无法实现目标的查询。

SELECT MNGR_CODE,
       MNGR_CODE2,
       lt.desc,
       l.reason,
       l.leaveID
FROM Leave l
     INNER JOIN lvtype lt ON l.typeid = lt.typeid
     LEFT OUTER HASH JOIN employee em ON em.Emp_Code = l.empcode
WHERE empcode IN ('AA', 'FF')
  AND leaveID IN (SELECT leaveID
                  FROM Leave l
                       INNER JOIN lvtype lt ON l.typeid = lt.typeid
                  WHERE l.empcode IN ('AA', 'FF')
                  GROUP BY l.empcode
                  HAVING SUM(lvdays) > 30);
sql sql-server group-by having
1个回答
0
投票

如果我正确地关注了您,则可以使用窗口功能:

select *
from (
    select 
        e.mngr_code,
        e.mngr_code2,
        lt.desc, 
        l.reason,
        l.leaveid,
        sum(l.lvdays) over(partition by e.empcode) sum_lvdays
    from leave l 
    inner join lvtype lt on l.typeid = lt.typeid 
    inner join employee em on em.emp_code = l.empcode
) t
where sum_lvdays > 30

子查询基于您现有的查询,并添加了一个附加列,该列对每个员工的所有叶子进行了窗口求和。外部查询使用窗口总和的结果作为过滤器。

我不确定您在子查询中确实需要left join,所以我将其更改为inner join

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