Laravel组按日期排列

Question

我试图为以下SQL做一个elqouent查询。

select sum(w.total_item_count) as Day_count, w.created_at as created_at from `sales_flat_orders` as `w` group by DATE(`w`.`created_at`) order by `w`.`created_at` asc

我已经尝试过这个

$orderbydate = DB::table('sales_flat_orders as w')
                ->select(array(DB::Raw('sum(w.total_item_count) as Day_count'),DB::Raw('DATE(w.created_at) as created_at')))
                ->groupBy('w.created_at')
                ->orderBy('w.created_at')
                ->get();

我在sql查询中得到了正确的输出，但在eloquent查询中没有得到正确的输出，请帮助，谢谢。

Answer 1

所以，伙计们，我已经得到了答案，谢谢你们阅读我的问题。

$orderbydate = DB::table('sales_flat_orders as w')
                ->select(array(DB::Raw('sum(w.total_item_count) as Day_count'),DB::Raw('DATE(w.created_at) day')))
                ->groupBy('day')
                ->orderBy('w.created_at')
                ->get();

我的查询中的Raw查询对created_at字段是错误的。现在好了。希望你也能从中得到一些启发。

Answer 2

$orderbydate = DB::table('sales_flat_orders as w')
                ->select(array(DB::Raw('sum(w.total_item_count) as 
                Day_count'),DB::Raw('DATE(w.created_at) as created_at')))
                ->orderBy('w.created_at')
                ->get();


$orderbydate->groupBy('w.created_at');