Python网页抓取

问题描述 投票:0回答:1

我只是想通过使用python从HTML中提取数据。(我需要data = 20%)任何有关这方面的帮助将不胜感激。

<div class="ratings-container">
  <div class="ratings">
    <div class="ratings active" style="width: 20%"></div>
  </div>
</div>

我不知道如何获得风格内容。以下类似代码的结果为NULL:

mratingNew = (tag.findAll('div',attrs={"class":"ratings active"})) 
for i in range(len(muserName)): 
    print(mratingNew[i].['style']) 
python-3.x web-scraping beautifulsoup jupyter-notebook html-parsing
1个回答
0
投票

您可以使用find获得宽度,并可以根据:进行拆分

from bs4 import BeautifulSoup

html = '''<div class="ratings-container">
  <div class="ratings">
 <div class="ratings active" style="width: 20%"></div>
   </div>
     </div>'''

soup = BeautifulSoup(html,"html.parser")
finddiv = soup.find('div',attrs={'class':'ratings active'})
style = finddiv['style']

style = style.split(':',1)[-1]
print style

输出:

 20%

如果您有多个具有相同类名的宽度,例如:

html = '''<div class="ratings-container">
 <div class="ratings">
 <div class="ratings active" style="width: 20%"></div>
 <div class="ratings active" style="width: 40%"></div>
 <div class="ratings active" style="width: 30%"></div>
   </div>
     </div>'''

您需要使用findAll并将其逐个拆分

find_last_div = soup.findAll('div',attrs={'class':'ratings active'})
for width_value in find_last_div:
    width_Get = width_value['style'].split(':',1)[-1]
    print width_Get

输出:

 20%
 40%
 30%
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