如何使用 golang 列出网络中的子网？

问题描述 投票：0回答：3

我想列出没有。网络中的子网，我有 python 中的示例工作代码，但在 golang 中需要它。

NETWORK="192.168.0.0/16"
subnet_prefix=22
net = ipaddress.ip_network(NETWORK)
for subnet in net.subnets(new_prefix=subnet_prefix):
    net = ipaddress.ip_interface(subnet)
    print(net)



192.168.0.0/22 192.168.4.0/22 192.168.8.0/22 192.168.12.0/22 192.168.16.0/22 192.168.20.0/22 192.168.24.0/22 192.168.28.0/22 192.168.32.0/22 192.168.36.0/22 192.168.40.0/22 192.168.44.0/22 192.168.48.0/22 192.168.52.0/22 192.168.56.0/22 192.168.60.0/22 192.168.64.0/22 192.168.68.0/22 192.168.72.0/22 192.168.76.0/22 192.168.80.0/22 192.168.84.0/22 192.168.88.0/22 192.168.92.0/22 192.168.96.0/22 192.168.100.0/22 192.168.104.0/22 192.168.108.0/22 192.168.112.0/22 192.168.116.0/22 192.168.120.0/22 192.168.124.0/22 192.168.128.0/22 192.168.132.0/22 192.168.136.0/22 192.168.140.0/22 192.168.144.0/22 192.168.148.0/22 192.168.152.0/22 192.168.156.0/22 192.168.160.0/22 192.168.164.0/22 192.168.168.0/22 192.168.172.0/22 192.168.176.0/22 192.168.180.0/22 192.168.184.0/22 192.168.188.0/22 192.168.192.0/22 192.168.196.0/22 192.168.200.0/22 192.168.204.0/22 192.168.208.0/22 192.168.212.0/22 192.168.216.0/22 192.168.220.0/22 192.168.224.0/22 192.168.228.0/22 192.168.232.0/22 192.168.236.0/22 192.168.240.0/22 192.168.244.0/22 192.168.248.0/22 192.168.252.0/22

go subnet
3个回答
3
投票

我编写的函数生成给定 

subnetMaskSize
的所有子网，这些子网可以在给定 
netCIDR
内创建。网络和子网均采用 CIDR 表示法。

例如：

func Runner() {
    fmt.Println(GenSubnetsInNetwork("192.168.0.0/24", 26))
}

=== RUN   TestRunner/run_me
[192.168.0.0/26 192.168.0.64/26 192.168.0.128/26 192.168.0.192/26] <nil>
--- PASS: TestRunner (0.00s)

我选择了算术运算，因此它更容易理解（为了获得更好的性能，请使用按位运算）。

该函数计算有关给定网络和子网掩码的一些事实，然后生成所有子网 CIDR。

func GenSubnetsInNetwork(netCIDR string, subnetMaskSize int) ([]string, error) {
    ip, ipNet, err := net.ParseCIDR(netCIDR)
    if err != nil {
        return nil, err
    }
    if !ip.Equal(ipNet.IP) {
        return nil, errors.New("netCIDR is not a valid network address")
    }
    netMaskSize, _ := ipNet.Mask.Size()
    if netMaskSize > int(subnetMaskSize) {
        return nil, errors.New("subnetMaskSize must be greater or equal than netMaskSize")
    }

    totalSubnetsInNetwork := math.Pow(2, float64(subnetMaskSize)-float64(netMaskSize))
    totalHostsInSubnet := math.Pow(2, 32-float64(subnetMaskSize))
    subnetIntAddresses := make([]uint32, int(totalSubnetsInNetwork))
    // first subnet address is same as the network address
    subnetIntAddresses[0] = ip2int(ip.To4())
    for i := 1; i < int(totalSubnetsInNetwork); i++ {
        subnetIntAddresses[i] = subnetIntAddresses[i-1] + uint32(totalHostsInSubnet)
    }

    subnetCIDRs := make([]string, 0)
    for _, sia := range subnetIntAddresses {
        subnetCIDRs = append(
            subnetCIDRs,
            int2ip(sia).String()+"/"+strconv.Itoa(int(subnetMaskSize)),
        )
    }
    return subnetCIDRs, nil
}

func ip2int(ip net.IP) uint32 {
    if len(ip) == 16 {
        panic("cannot convert IPv6 into uint32")
    }
    return binary.BigEndian.Uint32(ip)
}
func int2ip(nn uint32) net.IP {
    ip := make(net.IP, 4)
    binary.BigEndian.PutUint32(ip, nn)
    return ip
}
1
投票

所选答案对于 ipv4 效果很好，但我需要一个可以同时处理 ipv4 和 ipv6 的函数。这是我想出的；

package main

import (
    "fmt"
    "net"

    netaddr "github.com/dspinhirne/netaddr-go"
)

func breakIntoSubnets(network string, newCidr uint) ([]string, error) {
    ip, _, err := net.ParseCIDR(network)
    if err != nil {
        fmt.Println("Error:", err)
        return nil, err
    }

    if ip.To4() != nil {
        newCidr = 21
        parsedNetwork, err := netaddr.ParseIPv4Net(network)
        if err != nil {
            fmt.Printf("Error parsing network (%s) with netaddrr", network)
            return nil, err
        }
        subnets := make([]string, 0)
        for i := 0; i <= int(parsedNetwork.SubnetCount(newCidr)); i++ {
            subnet := parsedNetwork.NthSubnet(newCidr, uint32(i))
            if subnet == nil {
                return subnets, nil
            }
            subnets = append(subnets, subnet.String())
        }

        return subnets, nil
    } else {
        newCidr = 40
        parsedNetwork, err := netaddr.ParseIPv6Net(network)
        if err != nil {
            fmt.Printf("Error parsing network (%s) with netaddrr", network)
            return nil, err
        }
        subnets := make([]string, 0)
        for i := 0; i <= int(parsedNetwork.SubnetCount(newCidr)); i++ {
            subnet := parsedNetwork.NthSubnet(newCidr, uint64(i))
            if subnet == nil {
                return subnets, nil
            }
            subnets = append(subnets, subnet.String())
        }

        return subnets, nil
    }

}

func main() {
    subnets, err := breakIntoSubnets("2601:9000::/20", 48)

    if err != nil {
        fmt.Printf("Error: %v", err)
    }

    for _, subnet := range subnets {
        fmt.Println(subnet)
    }
}
0
投票

这只是 ipaddress-go 库 的几行代码。免责声明：我是图书馆的项目经理。

package main

import (
    "fmt"
    "github.com/seancfoley/ipaddress-go/ipaddr"
)

func main() {
    listSubnets("192.168.0.0/16", 22)
    listSubnets("2001:db8::1a20/124", 126)
}

func listSubnets(original string, newPrefix int) {
    subnet := ipaddr.NewIPAddressString(original).GetAddress()
    newSubnets := subnet.SetPrefixLen(newPrefix)
    iterator := newSubnets.PrefixBlockIterator()
    fmt.Println("subnets:")
    for iterator.HasNext() {
        fmt.Print(iterator.Next(), " ")
    }
    fmt.Println()
}


subnets: 192.168.0.0/22 192.168.4.0/22 192.168.8.0/22 192.168.12.0/22 192.168.16.0/22 192.168.20.0/22 192.168.24.0/22 192.168.28.0/22 192.168.32.0/22 192.168.36.0/22 192.168.40.0/22 192.168.44.0/22 192.168.48.0/22 192.168.52.0/22 192.168.56.0/22 192.168.60.0/22 192.168.64.0/22 192.168.68.0/22 192.168.72.0/22 192.168.76.0/22 192.168.80.0/22 192.168.84.0/22 192.168.88.0/22 192.168.92.0/22 192.168.96.0/22 192.168.100.0/22 192.168.104.0/22 192.168.108.0/22 192.168.112.0/22 192.168.116.0/22 192.168.120.0/22 192.168.124.0/22 192.168.128.0/22 192.168.132.0/22 192.168.136.0/22 192.168.140.0/22 192.168.144.0/22 192.168.148.0/22 192.168.152.0/22 192.168.156.0/22 192.168.160.0/22 192.168.164.0/22 192.168.168.0/22 192.168.172.0/22 192.168.176.0/22 192.168.180.0/22 192.168.184.0/22 192.168.188.0/22 192.168.192.0/22 192.168.196.0/22 192.168.200.0/22 192.168.204.0/22 192.168.208.0/22 192.168.212.0/22 192.168.216.0/22 192.168.220.0/22 192.168.224.0/22 192.168.228.0/22 192.168.232.0/22 192.168.236.0/22 192.168.240.0/22 192.168.244.0/22 192.168.248.0/22 192.168.252.0/22

subnets: 2001:db8::1a20/126 2001:db8::1a24/126 2001:db8::1a28/126 2001:db8::1a2c/126

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