[6 years ago,他们提出了一个很好的解决方案,但是我的更改导致了意外的结果,当我调用子菜单功能和主菜单时,窗口无法清除,帮助我了解问题所在。
import curses
from curses import panel
from test_print import get_menu_list, get_timings, time_to_seconds, GetPageChoise,\
main_menu_items, list_of_themes_end, text_discription_get
page = GetPageChoise()
class Menu(object):
def __init__(self, items, stdscreen):
self.window = stdscreen.subwin(5,2)
self.window.keypad(1)
self.panel = panel.new_panel(self.window)
self.panel.hide()
panel.update_panels()
self.position = 0
self.items = items
self.items.append(('exit','exit'))
def navigate(self, n):
self.position += n
if self.position < 0:
self.position = 0
elif self.position >= len(self.items):
self.position = len(self.items)-1
def display(self):
self.panel.top()
self.panel.show()
self.window.clear()
while True:
self.window.refresh()
curses.doupdate()
for index, item in enumerate(self.items):
if index == self.position:
mode = curses.A_REVERSE
else:
mode = curses.A_NORMAL
msg = '%d. %s' % (index, item[0])
self.window.addstr(10+ index, 1, msg, mode)
key = self.window.getch()
if key in [curses.KEY_ENTER, ord('\n')]:
if self.position == len(self.items)-1:
break
else:
self.items[self.position][1]()
elif key == curses.KEY_UP:
self.navigate(-1)
elif key == curses.KEY_DOWN:
self.navigate(1)
self.window.clear()
self.panel.hide()
panel.update_panels()
curses.doupdate()
class SubMenu(object):
def __init__(self, items, stdscreen):
self.window = stdscreen.subwin(5,2)
self.window.keypad(1)
self.panel = panel.new_panel(self.window)
self.panel.hide()
panel.update_panels()
self.position = 0
self.items = items
self.items.append(('exit','exit'))
def navigate(self, n):
self.position += n
if self.position < 0:
self.position = 0
elif self.position >= len(self.items):
self.position = len(self.items)-1
def display_sub(self):
while True:
self.window.refresh()
curses.doupdate()
for index, item in enumerate(self.items):
if index == self.position:
mode = curses.A_REVERSE
else:
mode = curses.A_NORMAL
next = 1
for disript in text_discription_get():
self.window.addstr(next, 1, disript)
next +=1
msg = '%d. %s' % (index, item[0])
self.window.addstr(10+ index, 1, msg, mode)
key = self.window.getch()
if key in [curses.KEY_ENTER, ord('\n')]:
if self.position == len(self.items)-1:
break
else:
self.items[self.position][1]()
elif key == curses.KEY_UP:
self.navigate(-1)
elif key == curses.KEY_DOWN:
self.navigate(1)
class MyApp(object):
def __init__(self, stdscreen):
self.screen = stdscreen
curses.curs_set(0)
submenu_items = [
('beep', curses.beep),
('flash', curses.flash)
]
submenu = SubMenu(sub_menu_items, self.screen) #Вывел конкретный подкаст, нужно изменить на выбор подкастов.
main_menu_items = [
('beep', curses.beep),
('flash', curses.flash),
('submenu', submenu.display_sub)
]
main_menu = Menu(main_menu_items, self.screen)
main_menu.display()
if __name__ == '__main__':
curses.wrapper(MyApp)
#Вывел меню, сделал выбор, нужно вывести Discription, сделать вызов плеера по выбору темы.
您可以在GIF上看到它的样子,事实是建议的解决方案不适合,因为子菜单应根据选择每次显示新内容。gif how work this
在显示该子菜单的功能之后对我有用的功能后插入clear()
:
class Menu(object):
...
def display(self):
...
if key in [curses.KEY_ENTER, ord('\n')]:
if self.position == len(self.items)-1:
break
else:
self.items[self.position][1]()
self.window.clear() # This will clear the main menu window every time an item is selected
您还应该清除显示另一个窗口的屏幕[[之前,因为如果子菜单小于主菜单,可能会发生相同的事情。
或者,您可以在每个循环的开始时清除窗口,因为您已经在每次按键后重新绘制列表。这样,您可以更新菜单中的项目,而不会像使用当前程序那样看到旧菜单的某些部分。